Question

Simplify completely the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the third power times y to the 2nd power all over 5 times x to the third power times y.
2x9y4 + 4x6y3
2x3y2 + 4xy
2x3y2 + 4y2
2x3y2 + 4y

Answer 1

Answer:

Option 4th is correct

$2x^3y^2+4y$

Step-by-step explanation:

GCF(Greatest common factor) is the largest number that divide the polynomial.

Given the statement:

the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the third power times y to the 2nd power all over 5 times x to the third power times y

⇒$\frac{10x^6y^3+20x^3y^2}{5x^3y}$

To simplify this expression:

GCF of $10x^6y^3$ and $20x^3y^2$ is, $10x^3y^2$

then;

$\frac{10x^3y^2(x^3y+2)}{5x^3y}$

⇒$2y(x^3y+2)$

Using distributive property: $a\cdot (b+c) = a\cdot b+ a\cdot c$

⇒$2x^3y^2+4y$

Therefore, the simplified expression is, $2x^3y^2+4y$

Answer 2

(10x^6y^3 + 20x^3y^2) / 5x^3y

10x^6y^3 / 5x^3y ⇒ 2x^3y^2
20x^3y^2 / 5x^3y ⇒ 4y

2x³y² + 4y   This is the simplified answer. The last option.