Answer:
The answer is "0.096".
Step-by-step explanation:
In this question, the X is a number of the students who enroll in a psycholog y course, follows a Poisson distribution with mean
![\therefore P(X=x)=\frac{e^{-105} 105^{x}}{x!},(x=0,1,2,3.....)\\\\\to p(teach\ two \ sections) = P(X \geq 119)\\\\=1-P(X](https://tex.z-dn.net/?f=%5Ctherefore%20P%28X%3Dx%29%3D%5Cfrac%7Be%5E%7B-105%7D%20105%5E%7Bx%7D%7D%7Bx%21%7D%2C%28x%3D0%2C1%2C2%2C3.....%29%5C%5C%5C%5C%5Cto%20p%28teach%5C%20%20two%20%5C%20sections%29%20%3D%20P%28X%20%5Cgeq%20119%29%5C%5C%5C%5C%3D1-P%28X%3C119%29%5C%5C%5C%5C%3D1-%5Csum_%7Bx%3D0%7D%5E%7B118%7DP%28X%3Dx%29%5C%5C%5C%5C%3D1-%5Csum_%7Bx%3D0%7D%5E%7B118%7D%5Cfrac%7Be%5E%7B-105%7D%20105%5E%7Bx%7D%7D%7Bx%21%7D%5C%5C%5C%5C%3D0.0956747863537%5C%5C%5C%5C%3D0.096%5C%5C)
Answer: 5/8 :)
Step-by-step explanation:
Y2-Y1
Over X2-X1 and then there is your slode
The answer is C.
90/105=6/7
Hope this helps!