Answer:
If Brianna's (I'll call her Bri in this situation) teacher says 3r + 5 and 4r are equal, you should definatly start by adding the 'r' value to the 3, which would be 8 afterwards. Bri is then incorrect because 4+5=9, and 9 is greater than 8, so Bri is wrong :'(...
Have a good day fellow lad,
AshlynnXOXO
Extraneous solutions mean "extra and not necessary"
Example: the area of a square = 16, what is the side of the square:
:If a is the side, the area is a²:
a² = 16, the square root of a = +√16 or a= - √16 :
a =4 or a = - 4 , Obviously you can't have a side of - 4, then this solution is an extraneous one
Answer:
y+9=-4(x-4)
Step-by-step explanation:
Point-slope is the equation y-y1=m(x-x1), where y1 is your y-coordinate and x1 is your x-coordinate.
<h3>Given</h3>
- an exponential curve with points (-3, 12) and (-2, 7)
- a horizontal asymptote of y=2
<h3>Find</h3>
- the equation of the curve
<h3>Solution</h3>
Since the horizontal asymptote of a plain exponential curve is y=0, your curve has been shifted up 2 units. So, we know the function is something of the form ...
... y = 2 + a·b^x
Putting in the given point values, we have
... 12 = 2 + a·b^(-3)
... 7 = 2 + a·b^(-2)
Subtracting 2 from each of these equations and finding their ratio gives
... (12-2)/(7-2) = (2+a·b^(-3) -2)/(2+a·b^(-2) -2)
... 10/5 = b^-1 . . . . . simplify
... b = 2^(-1) = 1/2
Then we can use either of the given data points to find <em>a</em>.
... 12 = 2 + a·(1/2)^(-3)
... 10 = 8a
... 10/8 = a = 1.25
So, the equation for the curve is ...
... y = 2 + 1.25·0.5^x
