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2 years ago

Brianna's teacher asks her if these two expressions 3r +5 and 4r are equivalent.

Mathematics

1 answer:

sukhopar [10]2 years ago

4 0

Answer:

If Brianna's (I'll call her Bri in this situation) teacher says 3r + 5 and 4r are equal, you should definatly start by adding the 'r' value to the 3, which would be 8 afterwards. Bri is then incorrect because 4+5=9, and 9 is greater than 8, so Bri is wrong :'(...

Have a good day fellow lad,

AshlynnXOXO

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The perimeter of a rectangle garden is 364 feet. If the width of the garden is 85 feet, what is it length?

kherson [118]

P=2(L+W)

P=364

L=99

sub and find W

364=2(99+W)

divide both sides by 2

182=99+w

subtract 99 from both sides

83=W

w=83ft

6 0

2 years ago

Water has a specific heat of 4.184 J/g°C and requires 23,000 J of heat to raise the

nasty-shy [4]

Answer:

$m=80.840 kg$

Step-by-step explanation:

Given Data,

Q=23000 J

c=4.184 J/g °c

Δt= 68 °c

m=?

By using this equation,

Q=mcΔt

$23000=m\times 4.184\times 68\\\\m=\frac{23000}{4.184\times68} \\\\\\m=80.840 kg$

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2 years ago

Item 18 You and your friend are selling tickets to a charity event. You sell 7 adult tickets and 16 student tickets for $120. Yo

Jobisdone [24]

$4

You can get this by setting up 2 equations. One for you and one for your friend. Each should have a cost equation. Let x = adult and y = student.

You: 7x + 16y = 120
Friend: 13x + 9 = 140

Solve using any method.

6 0

3 years ago

Read 2 more answers

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

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2 years ago

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Delvig [45]

Answer: If I am correct you should end up spending $74.06

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4 0

3 years ago