3 years ago

Let f(x)=x-3and h(x)=x2+6.what is (h⁰g)(1)

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

6 0

Answer:

The answer is 10 .

Step-by-step explanation:

f(x) = x-3

h(x) = $x^{2} +6$

Now ,

hog(1)

=h (1-3)

=h (-2)

= $(-2)^{2}$ +6

= 4+6

= 10

You might be interested in

Giovanni justifies whether the expression -4x-8 is equivalent to -2(x+1)-2(x+3)by letting x=3 in both expressions. What is the v

Anika [276]

For this case we have the following expressions:
-4x-8
-2 (x + 1) -2 (x + 3)
Evaluating x = 3 in both expressions we have:
-4 (3) -8 = -12 - 8 = -20
-2 (x + 1) -2 (x + 3) = -2 (3 + 1) -2 (3 + 3) = -2 (4) -2 (6) = -8-12 = -20
Answer:
the value of each expression when x = 3 is:
-20 and -20

6 0

3 years ago

Read 2 more answers

What is the measure of the angle that complements a 30° angle? 30° 60° 75° 90°

Paha777 [63]