Answer:
D. The methyl group of acetyl CoA becomes radio-labeled
Explanation:
During the steps in glycolysis, the carbon at position 1, becomes C-1 in dihydroxyacetone phosphate during the cleavage of fructose-1,6-bisphosphate to dihydroxyacetone phosphate and glyceraldehyde-3-phosphate. Subsequently on isomerization of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate, C-1 of dihydroxyacetone phosphate becomes C-3 of glyceraldehyde-3-phosphate.
Furthermore, in pyruvate, the end product of glycolysis, C-3 is converted to a methyl group which then becomes the methyl group in the acetyl-CoA molecule produced from the oxidative decarboxylation of pyruvate.
Since the radioactive 14-C of radio-labeled glucose occupies position 1, it will become the methyl group of acetyl-CoA.
A poxular exertion (the most common process for the creation of animal-based microorganisms) was in motion, which caused the formation of anti-biotic stem cells (or microorganisms). So that's how the microorganisms were likely formed.
If you're referring to the specifics and not the process of how the cells were made up, then those particular cells were made out of Fiber, Liquid, and RNA
Answer: b. the output of a system keeps conditions within the body absolutely constant only in a negative feedback loop.
Explanation:
In the negative feedback loop, the feedback reduces the excessive response of the stimulus for example regulation of body temperature, and control of blood glucose level. In the positive feedback loop, the response of a stimulus is intensified. Example, positive feedback is the childbirth and blood clotting. According to the negative feedback loop the output of the system keeps the internal body environment constant with respect to the changes in the external environment hence, maintains the homeostasis.
The genes are from the nuclei of the egg (from the female) and the sperm (from the male) the different traits are joined to create the particular genes.
(I might be right.)
