All categories

4 years ago

Complete the inequality statement 7/10 ___ 11/20 > < =

1 answer:

7 0

To start, give each fraction a common denominator by multiplying the 7/10 by two to get 14/20, an equivalent but not simplified fraction. now compare 14/20 and 11/20. 14/20 is greater than 11/20, so 7/10 > 11/20.

You might be interested in

A triangle in the coordinate plane has vertices of (2,6).(-4,-4), and (0,-6). The triangle is dilated with a scale factor of 2.

Serhud [2]

Answer:

To solve this problem you have to multiply all of the coordinates by 2

So your answers are

(2,6) ---> (4,12)

(-4,-4) ---> (-8,-8)

(0,-6) ---> (0,-12)

Could you please make brainly :)

Hope this helps ;)

Step-by-step explanation:

5 0

3 years ago

17. A hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm. Find

Pavlova-9 [17]

Answer:

$r = 3.74cm$

Step-by-step explanation:

Given

Hemisphere

$Radius = 7cm$

Cone

$Height = 49m$

Required

Determine the radius of the cone

First, we calculate the volume (V1) of the hemisphere.

$V_1 = \frac{2}{3}\pi r^3$

Substitute 7 for r

$V_1 = \frac{2}{3}\pi * 7^3$

$V_1 = \frac{2}{3}\pi * 343$

$V_1 = \frac{686}{3}\pi$

Volume (V2) of a cone is:

$V_2 = \frac{1}{3}\pi r^2h$

Because the lead is cast into a cone, then they have the same volume.

So, we have:

$\frac{686}{3}\pi = \frac{1}{3}\pi r^2h$

$686 = r^2h$

Substitute 49 for h

$686 = r^2 * 49$

Divide both sides by 49

$r^2 = \frac{686}{49}$

$r^2 = 14$

$r = \sqrt{14$

$r = 3.74cm$

<em>Hence, the radius of the cone is 3.74cm</em>

5 0

3 years ago

Six plus what equals -2

Rudiy27

Answer: -8

Step-by-step explanation:

6+ -8 = -2

7 0

3 years ago

(35 points)is x=1 and y=1 perpendicular or paralell to eachother or neither

Artyom0805 [142]

Perpendicular because y=1 goes across and x=1 goes vertical forming a right angle

4 0

3 years ago

Read 2 more answers

What is the measure of side AB

kkurt [141]

16 because the AB side gotta be a little bit bigger than the two other sides

8 0

3 years ago