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Ber [7]
3 years ago
5

Which of the following cannot be true about a linear pair of angles?

Mathematics
2 answers:
Sliva [168]3 years ago
7 0

Answer:

We need answeres to choose from

Step-by-step explanation:

lyudmila [28]3 years ago
7 0

A linear pair of angles cannot add up to anything other than 180 degrees.

They cannot be complementary because complementary means add up to 90 degrees.

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Write the number equal to 2 tens and 15 ones
leonid [27]
215    i hope this helped u
8 0
3 years ago
Simplify completely <br> (X^2+x-12/x^2-x-20)/(3x^2–24x+45/12x^2-48-60)
Rudik [331]

Answer:

(4 (x^4 - 20 x^2 - 12))/(3 x^2 (9 x^2 - 32 x - 144))

Step-by-step explanation:

Simplify the following:

(x^2 + x - x - 20 - 12/x^2)/((15 x^2)/4 + 3 x^2 - 24 x - 60 - 48)

Hint: | Put the fractions in x^2 + x - x - 20 - 12/x^2 over a common denominator.

Put each term in x^2 + x - x - 20 - 12/x^2 over the common denominator x^2: x^2 + x - x - 20 - 12/x^2 = x^4/x^2 + x^3/x^2 - x^3/x^2 - (20 x^2)/x^2 - 12/x^2:

(x^4/x^2 + x^3/x^2 - x^3/x^2 - (20 x^2)/x^2 - 12/x^2)/((45 x^2)/12 + 3 x^2 - 24 x - 60 - 48)

Hint: | Combine x^4/x^2 + x^3/x^2 - x^3/x^2 - (20 x^2)/x^2 - 12/x^2 into a single fraction.

x^4/x^2 + x^3/x^2 - x^3/x^2 - (20 x^2)/x^2 - 12/x^2 = (x^4 + x^3 - x^3 - 20 x^2 - 12)/x^2:

((x^4 + x^3 - x^3 - 20 x^2 - 12)/x^2)/((45 x^2)/12 + 3 x^2 - 24 x - 60 - 48)

Hint: | Group like terms in x^4 + x^3 - x^3 - 20 x^2 - 12.

Grouping like terms, x^4 + x^3 - x^3 - 20 x^2 - 12 = x^4 - 20 x^2 - 12 + (x^3 - x^3):

(x^4 - 20 x^2 - 12 + (x^3 - x^3))/(x^2 ((45 x^2)/12 + 3 x^2 - 24 x - 60 - 48))

Hint: | Look for the difference of two identical terms.

x^3 - x^3 = 0:

((x^4 - 20 x^2 - 12)/x^2)/((45 x^2)/12 + 3 x^2 - 24 x - 60 - 48)

Hint: | In (45 x^2)/12, the numbers 45 in the numerator and 12 in the denominator have gcd greater than one.

The gcd of 45 and 12 is 3, so (45 x^2)/12 = ((3×15) x^2)/(3×4) = 3/3×(15 x^2)/4 = (15 x^2)/4:

(x^4 - 20 x^2 - 12)/(x^2 (15 x^2/4 + 3 x^2 - 24 x - 60 - 48))

Hint: | Put the fractions in (15 x^2)/4 + 3 x^2 - 24 x - 60 - 48 over a common denominator.

Put each term in (15 x^2)/4 + 3 x^2 - 24 x - 60 - 48 over the common denominator 4: (15 x^2)/4 + 3 x^2 - 24 x - 60 - 48 = (15 x^2)/4 + (12 x^2)/4 - (96 x)/4 - 240/4 - 192/4:

(x^4 - 20 x^2 - 12)/(x^2 (15 x^2)/4 + (12 x^2)/4 - (96 x)/4 - 240/4 - 192/4)

Hint: | Combine (15 x^2)/4 + (12 x^2)/4 - (96 x)/4 - 240/4 - 192/4 into a single fraction.

(15 x^2)/4 + (12 x^2)/4 - (96 x)/4 - 240/4 - 192/4 = (15 x^2 + 12 x^2 - 96 x - 240 - 192)/4:

(x^4 - 20 x^2 - 12)/(x^2 (15 x^2 + 12 x^2 - 96 x - 240 - 192)/4)

Hint: | Group like terms in 15 x^2 + 12 x^2 - 96 x - 240 - 192.

Grouping like terms, 15 x^2 + 12 x^2 - 96 x - 240 - 192 = (12 x^2 + 15 x^2) - 96 x + (-192 - 240):

(x^4 - 20 x^2 - 12)/(x^2 ((12 x^2 + 15 x^2) - 96 x + (-192 - 240))/4)

Hint: | Add like terms in 12 x^2 + 15 x^2.

12 x^2 + 15 x^2 = 27 x^2:

(x^4 - 20 x^2 - 12)/(x^2 (27 x^2 - 96 x + (-192 - 240))/4)

Hint: | Evaluate -192 - 240.

-192 - 240 = -432:

(x^4 - 20 x^2 - 12)/(x^2 (27 x^2 - 96 x + -432)/4)

Hint: | Factor out the greatest common divisor of the coefficients of 27 x^2 - 96 x - 432.

Factor 3 out of 27 x^2 - 96 x - 432:

(x^4 - 20 x^2 - 12)/(x^2 (3 (9 x^2 - 32 x - 144))/4)

Hint: | Write ((x^4 - 20 x^2 - 12)/x^2)/((3 (9 x^2 - 32 x - 144))/4) as a single fraction.

Multiply the numerator by the reciprocal of the denominator, ((x^4 - 20 x^2 - 12)/x^2)/((3 (9 x^2 - 32 x - 144))/4) = (x^4 - 20 x^2 - 12)/x^2×4/(3 (9 x^2 - 32 x - 144)):

Answer: (4 (x^4 - 20 x^2 - 12))/(3 x^2 (9 x^2 - 32 x - 144))

3 0
3 years ago
Find the complete factored form of the polynomial -8a^4b^5+4a^2b^4
Zigmanuir [339]

Answer:

The completely factored polynomial is:

⇒ -4a^2b^4(2a^2b-1)  

Step-by-step explanation:

Given polynomial:

-8a^4b^5+4a^2b^4

To factor the given polynomial completely.

Solution:

In order to factor the given polynomial, we will  find the greatest common factor of the terms and then factor them out by dividing the term by its G.C.F.

The factors can be listed as:

-8a^4b^5=-1\times 2\times 2\times 2\times a\times a\times a\times a\times b\times b \times b\times b \times b

4a^2b^4=2\times 2\times a\times a\times b\times b \times b\times b

From the factors listed the GCF can be given as = 2\times 2 \times a\times a \times b \times b\times b \times b

GCF = 4a^2b^4

Factoring out the GCF.

4a^2b^4(-2a^2b+1)

The above expression can be simplified by factoring out -1.

-4a^2b^4(2a^2b-1)      (Answer)

5 0
3 years ago
Read 2 more answers
3) Katie’s family went out to dinner. The dinner bill was $85 and the family gave the server a 20% tip. a) What’s the tip? Pleas
Anni [7]

Answer:

<u>Part A: US$ 17</u>

<u>Part B : US$ 102</u>

Step-by-step explanation:

1. Let's check all the information given to us to answer the question correctly:

Dinner bill = US$ 85

Tip to the server = 20% of the bill

2. What’s the tip?

20% = 0.2

Tip to the server = 0.2 * 85

<u>Tip to the server = 17</u>

3. What’s the total of the dinner?

Total of the dinner = Dinner bill + Tip to the server

Total of the dinner = 85 + 17

<u>Total of the dinner = 102</u>

5 0
4 years ago
How many solutions does the system of equations have 3x=-12+15 and x + 4y =5
Sphinxa [80]

Answer:

infinitely many solutions

Step-by-step explanation:

I assume that you meant

3x = -12y + 15 and x + 4y =5 (you accidentally omitted the 'y')

Multiplying the second equation by 3 yields

3x + 12y = 15

... which is identical to the first equation.  Thus, the two lines coincide, and we conclude that there are infinitely many solutions.

6 0
3 years ago
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