please explain what question you are talking about since there is 6 questions on the paper.
Original number is 20, so 4/5= 16
Answer:
y - 2 = 0
Step-by-step explanation:
find slope first:
(2-2)/(5+1) = 0/6 or 0
now use 'y=mx+b' to find the y-intercept (the 'b'):
2 = 0(5) + b
2 = b
so, in slope-intercept form, the equation is:
y = 2
but, in standard form, the equation is:
y - 2 = 0
<span>Before all let's just convert Km/s into m/s :
2.41 km/s = 2410m/s\
To solve the second part
First we have to find Vy
Vy = 2410 m/s * sin 61.5
= 2410 m/s * 0.8788
=2117.908 m/s.
When the shell reaches it's maximum height the vertical velocity component will be zero
based on that theorem let's apply linear motion equation
V = u + at
0 = 2117.908 m/s - 9.8 m/S^2 * (t)
t = 216.1130 s
As the shell has to go upward and comes back to earth the shell will require a same amount of time in order to reach earth again so the total time that shell will spend on the air will be
<span>2*t
= 432.226 s
I hope my answer has come to your help. Have a nice day ahead and may God bless you always!</span></span>
