To do this, we must use the unit circle. At the angle $\frac{\pi }{6}$ the coordinate pair is ( $\frac{\sqrt{3} }{2}$ , $\frac{1}{2}$ ) and the hypotenuse is 1

Now that we know these we can start using the trig functions

sin = y

cos = x

tan = $\frac{y}{x}$

And the other functions would be the reciprocal of these

csc = $\frac{1}{y}$

sec = $\frac{1}{x}$

cot = $\frac{x}{y}$

This would mean that

sinx = $\frac{1}{2}$

cosx = $\frac{\sqrt{3} }{2}$

tanx = $\frac{1}{\sqrt{3} }$ or $\frac{\sqrt{3} }{3}$ if you're supposed to rationalize your denominators

cscx = 2

secx = $\frac{2}{\sqrt{3} }$ or $\frac{2\sqrt{3} }{3}$

cot = $\sqrt{3}$

6 0

3 years ago

Did I do this right? In △RST, VT=60 in. What is the length of TX¯¯¯¯¯?

Tems11 [23]

Yes! In △RST, VT=60 in. What is the length of TX¯¯¯¯¯? It is 40 in.

3 0

3 years ago

Please help asap! 13 points!

Step2247 [10]

B that's your answer

7 0

3 years ago

Help ASAP with 10&11 ASAP thanksss

kari74 [83]

10 is 287.9999 m squared and 11 is 2,435.125 yards squared

6 0

3 years ago