Question

Can someone help me?

Answer 1

Answer:

Step-by-step explanation:

To do this, we must use the unit circle. At the angle $\frac{\pi }{6}$ the coordinate pair is ($\frac{\sqrt{3} }{2}$, $\frac{1}{2}$) and the hypotenuse is 1

Now that we know these we can start using the trig functions

sin = y

cos = x

tan = $\frac{y}{x}$

And the other functions would be the reciprocal of these

csc = $\frac{1}{y}$

sec = $\frac{1}{x}$

cot = $\frac{x}{y}$

This would mean that

sinx = $\frac{1}{2}$

cosx =$\frac{\sqrt{3} }{2}$

tanx =$\frac{1}{\sqrt{3} }$ or $\frac{\sqrt{3} }{3}$ if you're supposed to rationalize your denominators

cscx = 2

secx = $\frac{2}{\sqrt{3} }$ or $\frac{2\sqrt{3} }{3}$

cot = $\sqrt{3}$