Answer:
4.1145
Step-by-step explanation:
You can use the following formula to solve this kind of problems,

So, let's start of with log4_(300). Since the question have already gave log4_(3) =0.7925 and log4_(5) =1.1610. It means that you have to split the 300 into the simplest form where almost all of the numbers are 3 and 5.

Answer:
Theoretical probability
Step-by-step explanation:
The theoretical probability is defined as:

In this case we look for the probability of taking a 2 out of the bag. As there is only one paper with the number 2 in the bag then:
number of desired results = 1
The amount of paper in the bag is equal to 7, so:
number of possible results = 7
Thus:

This is a theoretical probability, since we do not need to perform the experiment to calculate the probability.
To calculate the experimental probability we must perform the following experiment:
Take a paper out of the bag, record the number obtained and then return the paper to the bag.
Now repeat this experiment n times. (Perform n trials)
So:

To calculate a theoretical probability you always need to perform an experiment with n trials.
Answer:
your answer is B
Step-by-step explanation:
Answer:
The scale factor of a dilation from ABCD to RSTU is 
Step-by-step explanation:
We know that the rectangle ABCD is similar to rectangle RSTU.
Given that in rectangle ABCD the longest sides are DC and AB and in the rectangle RSTU the longest sides are UT and RS ⇒ The scale factor of a dilation will transform the sides DC and AB into UT and RS
Working with the lengths of the sides :
DC.(Scale factor) = UT
AB.(Scale factor) = RS
Replacing with the values of the lengths (Scale factor : SF) :


Notice that the scale factor is dimensionless.
We can verify this result with the sides AD and BC :


The scale factor (SF) is 