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Komok [63]
2 years ago
12

PLEASE help me with these thanks

Mathematics
1 answer:
Sladkaya [172]2 years ago
3 0
7.) 6 + 9 = 15t - 6 = 9t + 2 = 11t
15t-4
Answer: A.)
8.) f^+2+3
f^5
Answer: A.)
9.)
144^14 = 1.6e30
144^220736
1.6e30/220736 = 7.9e25
/7.9e25 = 144^28
Answer: C.)
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What is the answer to 7(1 + 4k)
Sophie [7]
How to solve it:
•1. multiply 7 x 1= 7
•2. multiply 7 x 4k= 28k

so the answer is: 7+28k

i hope i have been helpful :)
8 0
3 years ago
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In health class, Baldwin is learning about making healthy food choices. For a lesson on
xxTIMURxx [149]

Answer:

There are 3.1 fibers in rhe banana

Step-by-step explanation:

6.8-3.7=3.1

6 0
2 years ago
Which expression means “ multiply 3 by the sum of m and p “
charle [14.2K]

Answer:

3m+3p

Step-by-step explanation:

Sum of m and p is expressed as;

m + p (sum means addition)

If 3 is multiplied  by the sum, this is expressed as;

3(m+p)

Expand

3m + 3p

Hence the required expression is 3m+3p

8 0
3 years ago
Can anyone help me with this please
olga_2 [115]

Hi there!

\large\boxed{\frac{1}{4}, -\frac{3}{2}}

13y² + 10y - 3 = 5y²

Begin by moving all terms to one side:

13y² + 10y - 3 - 5y² = 0

Combine like terms:

8y² + 10y - 3 = 0

Factor using the guess-and-check method.

(4y - 1)(2y + 3) = 0

Set each factor equal to 0 to find the solutions:

4y - 1 = 0

4y = 1

y = 1/4

2y + 3 = 0

2y = -3

y = -3/2

8 0
2 years ago
Find an equation for those points P such that the distance from P to A(0, 1, 2) is equal to the distance from P to B(6, 4, 2). W
suter [353]

Answer:  The required equation for points P is 4x+2y=17.

Step-by-step explanation: We are give two points A(0, 1, 2) and B(6, 4, 2).

To find the equation for points P such that the distance of P from both A and B are equal.

We know that the distance between two points R(a, b, c) and S(d, e, f) is given by

RS=\sqrt{(d-a)^2+(e-b)^2+(f-c)^2}.

Let the point P be represented by (x, y, z).

According to the given information, we have

PA=PB\\\\\Rightarrow \sqrt{(x-0)^2+(y-1)^2+(z-2)^2}=\sqrt{(x-6)^2+(y-4)^2+(z-2)^2}\\\\\Rightarrow x^2+y^2-2y+1+z^2-4z+4=x^2-12x+36+y^2-8y+16+z^2-4z+4~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow -2y+1=-12x-8y+52\\\\\Rightarrow 12x+6y=51\\\\\Rightarrow 4x+2y=17.

Thus, the required equation for points P is 4x+2y=17.

8 0
3 years ago
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