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forsale [732]
3 years ago
14

-1/9+-5/9= Simplest form 24 points

Mathematics
2 answers:
Tom [10]3 years ago
8 0

-1/9+-5/9=


-1+5/9= -6/9


-6/9= -2×3/3×3= - 2/3



Nataly [62]3 years ago
5 0

-1/9+-5/9=

When you are adding a negative number, the operation turns into subtraction:

-1/9-5/9=\frac{-1-5}{9}=-\frac{6}{9}=-\frac{2}{3}

Really, it's just subtraction. The simplest form is -2/3, which is equal to -0.66667.

I hope this helps :)

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8% write left handed.
90+60=150
9+3=12
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The response of randomly-selected people to the question, "how many hours of sleep did you get last night?"
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Minnie organizes data in a table to show the net change in the number of people subscribing and unsubscribing to her blog each m
olchik [2.2K]

The factored expression which represents the net change in the number of blog subscriptions over 10 months is :

  • 3(11 - 7) + 4(-8)
  • Hence, the net change is -20

Change : -8, 11, -7, -7, -7, -8, -8, -8, 11, 11

To factor the values in the change variable :

-7 has a frequency of 3

-8 has a frequency of 4

11 has a frequency of 3

Values having the same frequency can be factored together :

Hence, we have ;

3(11 - 7) = 3(11 - 7) = 3(4) = 12 - - - - (1)

-8 having a value of 4 can be factored thus ; 4(-8) = -32 - - (2)

Joining both equations :

3(11-7) + 4(-8)

3(11 - 7) + 4(-8)

3(4) + 4(-8)

12 + (-32)

= - 20

Therefore, the factored expression for the net change in subscription is 3(11-7) + 4(-8)

Learn more :brainly.com/question/18904995

8 0
2 years ago
What is the first step in solving 5 + = 3?
storchak [24]

Answer:

c subtract 5 from both sides

7 0
1 year ago
What is the value of X?
d1i1m1o1n [39]

Answer:

x=10

Step-by-step explanation:

We can use the angle bisector theorem to solve this problem

8             12

-------- = ---------

x+4         2x+1

Using cross products

8(2x+1) = 12(x+4)

Distribute

16x+8 = 12x+48

Subtract 12x from each side

16x -12x +8 = 12x-12x +48

4x +8 = 48

Subtract 8 from each side

4x+8-8 = 48-8

4x = 40

4x/4 = 40/4

x=10

3 0
3 years ago
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