Look at the equation below.

Line L has equation y = 4x - 7, and line M is parallel to line L and passes through the point (2, 15). Determine the equation of

yarga [219]

Answer:

y=4x+7

Step-by-step explanation:

Line M is parallel to line L, so the equation for line M is y=4x+b

Plug in the coordinates of point (2,15), you get:

15=4*2+b

Solve that to get b=7

Therefore the equation of Line M is y=4x+7

5 0

3 years ago

What two-dimensional shape is formed by a cross section of the cone shown from the vertex perpendicular to the base of the cone?

Ber [7]

The correct choice is D!

Hope this helped you out! :)

8 0

3 years ago

Write an expression involving integers for each statement a) moving 4 steps left, then moving 9 steps right b) on 3 separate occ

Nostrana [21]

Answer:

(a) $-4+9$

(b) $-2 \times 3$

Step-by-step explanation:

Part A

Moving 4 steps left, then moving 9 steps right

When you move left, we indicate with a negative sign while a move right is indicated with a positive sign.

Moving 4 steps left = -4

Moving 9 steps right = +9

Therefore, an expression for the statement is: $-4+9$

Part B

When you lose or owe in word problems, it is usually indicated using a negative sign.

Therefore, the statement Shari lost 2 pencils can be represented with the integer: -2

Since Shari lost 2 pencils on 3 occasions, we simply have:

$-2 \times 3$

3 0

2 years ago

"A student made the following chart to prove that AB2 + BC2 = AC2.

katovenus [111]

Step 3 has an error.

Step-by-step explanation:

Similarity-criteria of triangles:

1. All the corresponding angles of two triangles should be equal.

2. The ratio between the corresponding sides of two triangles should be equal.

In $\triangle ABC$ and $\triangle BDC$

$\angle BAC = \angle DBC \\\angle ACB = \angle BCD$

All the angles of triangle are equal.

∴ $\triangle ABC \sim \triangle BDC$

Since, $\triangle ABC \sim \triangle BDC$

$\frac{AC}{BC}=\frac{AC}{DC}$

$BC^{2}=AC \times DC$

In $\triangle ABC$ and $\triangle BDA$ ,

$\fbox{\begin\\ \angle ABC= \angle BDA = 90^{\circ}\end{minispace}}$

$\fbox{\begin \\\angle BAC = \angle BAD\\\end{minispace}}$

$\angle ACB = \angle ABD$

All the angles of triangle are equal.

∴ $\fbox{\begin\triangle ABC \sim \triangle BDA \end{minispace}}$

∵ $\triangle ABC \sim \triangle BDA$

$\frac{AC}{AB}=\frac{AB}{AD}$

$AB^{2}=AC \times AD$

Now, $AB^{2}+BC^{2}$ can be simplified as,

$AB^{2}+BC^{2}=AC \times AD+AC \times DC\\AB^{2}+BC^{2}=AC(AD+DC)\\AB^{2}+BC^{2}=AC(AC)\\AB^{2}+BC^{2}=AC^{2}$

Learn more:

1. Find the height of the triangle?

brainly.com/question/12989306

2. Which undefined term is needed to define an angle? brainly.com/question/3717797

3. Look at the figure, which trigonometric ratio should you use to find x? brainly.com/question/9880052

Answer Details

Grade: Junior High School

Subject: Mathematics

Chapter: Triangle

Keywords: triangle, similar, similarity, ratio of sides, right triangle, similar triangle, ratio of sides, equal angles, square of hypotenuse, sum, square of legs, sum of square of legs

8 0

3 years ago

What is the value of x? A 6x - 3 3x + 6 B. 5x 3 4 05 02

choli [55]

Unclear plssss make it clear

4 0

2 years ago