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nirvana33 [79]
4 years ago
10

Solve the equation for the indicated variable.1. y= 3/8 (x+4) for x​

Mathematics
2 answers:
Bess [88]4 years ago
8 0

Answer:

\large\boxed{x=\dfrac{8}{3}y-4}

Step-by-step explanation:

\dfrac{3}{8}(x+4)=y\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{3}{8\!\!\!\!\diagup_1}(x+4)=8y\\\\3(x+4)=8y\qquad\text{divide both sides by 3}\\\\\dfrac{3(x+4)}{3}=\dfrac{8y}{3}\\\\x+4=\dfrac{8}{3}y\qquad\text{subtract 4 from both sides}\\\\x=\dfrac{8}{3}y-4

madam [21]4 years ago
6 0

Answer:

x=8y/3-4

Step-by-step explanation:

What we have to do to solve for X into re arrange the equation so that X is by itself on one side of the equation.  To start we will divide both sides by 3/8 to move it away from the X side and we get

8y/3=x+4 then we will subtract both sides by 4 to get x all by itself

8y/3-4=x

I hope this helps and please don't hesitate to ask if there is anything still unclear!

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3 years ago
An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

8 0
3 years ago
Add<br>(4-4i)+(3-2i)<br>Write as complex number in standard form​
Viefleur [7K]

Answer: (4-4i)+(3-2i) = 7-6i

Step-by-step explanation:

To add or subtract two complex numbers, just add or subtract the corresponding real and imaginary parts. For instance, the sum of 4 -4i and 3 - 2i is 7 -6i. The numbers in standard form will be a + bi, where a is the real part and bi is the imaginary part.

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y = mx+b

So, if you do that, you'll get (remember, this is <em>after</em> solving for y):
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Hope this helps.
7 0
3 years ago
Read 2 more answers
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