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3 years ago

8

Can someone please answer these 4 questions they don’t look hard- but I just need to understand please!! (If you can provide the

answer please!!!!!)

1 answer:

Nostrana [21]3 years ago

6 0

Answer:

Thanks for the points

Step-by-step explanation:

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FAST ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

lana [24]

Answer:

0.5

Step-by-step explanation:

just use any point you can find in the graph

and use the dollar to divided by the cups.

the point I chose is 1 dollar for 2 cups. So it's 0.5 dollar for 1cup

5 0

3 years ago

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

<h2>Why?</h2>

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

3 years ago

9000 dollars is placed in an account with an annual interest rate of 8%. How much will be in the account after 17 years, to the

Fed [463]

Answer:

$33,300.16

Step-by-step explanation:

7 0

3 years ago

for the month of March Cassie plans to vacuum her floor every fourth day and clean her bathroom every 7th day if she begins this

Akimi4 [234]

Answer:

Tuesday march 5th she will vacuum her floor. Friday march 8th she will clean her bathroom.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A rope is tied around two trees. The lower end of the rope is 6

GrogVix [38]

Slope is the difference in height/difference in distance.

starting from the higher point to the lower point.

So the equation will be

(12-6)/6=6/6=1

The slope of the rope is 1 according to the given information

Hope it helped! :D

3 0

3 years ago