All categories

3 years ago

A submarine was situated 800 feet below sea level. If it ascends 250 feet, what is its new position?

Mathematics

2 answers:

ohaa [14]3 years ago

5 0

The submarine's new position is 550 Feet

Anarel [89]3 years ago

3 0

550 feet below sea level

You might be interested in

Y=1/4x−2y=−2x+3 help solve problem.

8_murik_8 [283]

Answer:

(x, y) = (2 2/9, -1 4/9)

Step-by-step explanation:

Equate the values of y and solve for x.

1/4x -2 = -2x +3

(2 1/4)x = 5 . . . . . . . . add 2+2x to both sides

x = 20/9 = 2 2/9 . . . multiply by 4/9

y = -2(2 2/9) +3 = -4 4/9 +3 . . . . substitute for x in the second equation

y = -1 4/9

The solution is x = 2 2/9, y = -1 4/9.

7 0

3 years ago

Josiah takes a multiple-choice quiz that has three questions. Each question has five answer options. If he randomly chooses his

ahrayia [7]

The answer is 1/125.

6 0

3 years ago

Read 2 more answers

When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra

Sergeu [11.5K]

Answer:

$r=\sqrt{10}\text{ m}$

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

$V=\pi r^2h$ , where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be $h = 0.7$ meters at $V=22\text{ m}^3$ .

Upon substituting these values in above formula, we will get:

$22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})$

$22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}$

$\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2$

$r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}$

$r^2=10\text{ m}^2$

Now, we will take positive square root of both sides as radius cannot be negative.

$\sqrt{r^2}=\sqrt{10\text{ m}^2}$

$r=\sqrt{10}\text{ m}$

Therefore, radius of tank would be approximately square root of 10 m.

5 0

3 years ago

PLZZZZ HELLLLPPPP WILL MARK BRAINIEST LOTS OF POINTSSS PLZZZZ HURRRY

Anni [7]

The first box is 3 more than the quotient of 6 and a number, the second is 6 less than the product of 3 and a number, the third box is the product of 6 and the sum of a number and 3.

7 0

3 years ago

Read 2 more answers

20 points. I’m struggling with this part, and pls explain so I can understand and do it by my self in the next page.

lesantik [10]

For the first 3 you just have to divide (forget about the square root for now) and then reduce its result by finding two numbers (one of them have to be able to be squared rotted) that multiplied gives the fist result. Then you just have to square root one of the numbers and leave the other one as it is.

For the last 4; you cannot have radicals in the denominator, so you have to multiply both top and bottom by the square root, after that you just reduce.

Hope you understand, if you have any questions please let me know.

8 0

3 years ago