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2 years ago

Which of the following expressions is a fifth-degree binomial?

Mathematics

2 answers:

Maurinko [17]2 years ago

7 0

Answer:

Step-by-step explanation:

Degree of a polynomial is the highest power contained by variable or two variable being multiplied so

The degrees of polynomial in the above options are

A) 9(5+4=9)

B)7(1+6)

C)5

D)2

Juli2301 [7.4K]2 years ago

6 0

It’s definitely the letter d

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Hi, please help me out with this math problem.

GalinKa [24]

9514 1404 393

Answer:

x - 4

Step-by-step explanation:

The expression simplifies to ...

$\sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|$

For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...

x - 4 . . . . for x ≥ 4

6 0

2 years ago

PLEASEE HELP ANYONE

Grace [21]

1- Leave the 1st case empty

2- Write on the 1st row each element of the trinomial in each case

3-Write on the 1st column in each case each of the element of the binomial

║ y² -3y 9
----------- ║-----------------------------------------------------
y ║    y³ -3y²    9y
----------- ║---------------------------------------------------
3 ║    3y²    -9y    27
------------║----------------------------------------------------
   TOTAL║(y³+3y²) +(-3y²-9y) + ( 9y+27)

If you add the Total you will get: (A) Y³+27

6 0

2 years ago

Calculating cos-1 ( help is gladly appreciated :) )

Alekssandra [29.7K]

Answer:

$\frac{3\pi}{4}$

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by $\frac{180^\circ}{\pi}$ giving you:

$\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}$ .

We can do this since $\pi \text{ rad }=180^\circ$ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

$\cos^{-1}(x)$ is going to output an angle measurement in $[0,\pi]$ .

So we are looking to solve the following equation in that interval:

$\cos(x)=-\frac{\sqrt{2}}{2}$ .

This happens in the second quadrant on the given interval.

The solution to the equation is $\frac{3\pi}{4}$ .

So we are saying that $\cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2}$ implies $\cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4}$ since $\frac{3\pi}{4} \in [0,\pi]$ .