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3 years ago

9

A sweater cost$12 more than a shirt.together they cost$46.what was the price of the shirt

2 answers:

Dmitry [639]3 years ago

6 0

The shirt cost 34 dollars.

alina1380 [7]3 years ago

3 0

Make the shirt equal x, and so the sweater is x + 12. Together they equal 46, so your equation is x + x + 12 = 46, which simplifies to 2x + 12 = 46. Subtract 12 from both sides, and you have 2x = 34. Divide both sides by two, and you have x = 17. The shirt is $17.

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At video shack, Movie rentals cost $3.99 each. The cost of renting three movies in one video game is $.11 less than the cost of

goldenfox [79]

Think of it like this
3.99 x 3=11.97
Divide by 4
Should give u 2.99
^^^there is your answer

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3 years ago

Explain how you can use absolute value to tell wether the sum of two integers is positive or negative

Rudiy27

Step-by-step explanation:

Using absolute value to tell wether the sum of two integers is positive or negative.

Suppose we have a positive integer,

x and a negative interger, -x and we want to find their sum, we take the absolute values of each of the integers, that is |x| and |-x|. Then we subtract these values: |x| - |-x|. If the larger integer is positive, the result of the difference is positive, but if the larger number is negative, the result of the difference is negative.

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3 years ago

What is the solution: <br><br> 256x + 2 = 43x + 9

ruslelena [56]

<u>Answer:</u>

$x = \bf \frac{7}{213}$

<u>Step-by-step explanation:</u>

To find the solution to the equation, we have to rearrange the equation to make $x$ the subject:

$256x + 2 = 43x + 9$

⇒ $256x + 2 - 2 = 43x + 9 - 2$ [Subtracting 2 from both sides]

⇒ $256x = 43x + 7$

⇒ $256x - 43x = 43x + 7 - 43x$ [Subtracting $43x$ from each side]

⇒ $213x = 7$

⇒ $\frac{213}{213}x = \frac{7}{213}$ [Diving both sides by 213]

⇒ $x = \bf \frac{7}{213}$

3 0

1 year ago

Read 2 more answers

Co-ordinate Geometry

saul85 [17]

Answer:

The value of a = 14

Step-by-step explanation:

Given

(x₁, y₁) = (2, 4)

(x₂, y₂) = (6, a)

(x₃, y₃) = (-1, 1)

A = 9 sq.units

Area of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃) is:

$A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}$

substituting the values (x₁, y₁) = (2, 4), (x₂, y₂) = (6, a), (x₃, y₃) = (-1, 1), A = 9 in th formula

$A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}$

$9=\frac{\left|2\left(a-1\right)+6\left(1-4\right)+-1\left(4-a\right)\right|}{2}$

Multiply both sides by 2

$\frac{2\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|}{2}=9\cdot \:2$

simplify

$\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|=18$

As the area is always positive.

so

$2\left(a-1\right)+6\left(1-4\right)-1\cdot \left(4-a\right)=18$

$2\left(a-1\right)-18-\left(4-a\right)=18$

Add 18 to both sides

$2\left(a-1\right)-18-\left(4-a\right)+18=18+18$

simplify

$2\left(a-1\right)-\left(4-a\right)=36$

$3a-6=36$

$3a=42$

Divide both sides by 3

$\frac{3a}{3}=\frac{42}{3}$

$a=14$

Thus, the value of a = 14

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3 years ago

Find the value of the variable.

Gre4nikov [31]

Answer:

x=y[base side of isosceles triangle]

x²+y²=19²

x=√{19²/2)}

x=13.44

y=13.44

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3 years ago