Answer:
Step-by-step explanation:
(a/5) - (b/3) = (a/2) - (b/6)
+(B/3) + (b/3)
NOTE: use property of equality to isolate <em>b</em> from <em>a</em>
(a/5) = (b/3) + (a/2) - (b/6)
-(a/2) - (a/2)
NOTE: continue to use property of equality to isolate <em>a</em><em> </em>from <em>b</em>
(a/5) - (a/2) = (b/3) - (b/6)
60((a/5) - (a/2)) = ((b/3) - (b/6))60
NOTE: 60 is a common multiple of 5, 2, 3, and 6
12a - 30a = 20b - 10b
NOTE: combine alike terms
-17a = 10b
-17a/-17 = 10b/-17
NOTE: decide by -16 to find what a is equal to
Final answer
Chin is correct because 5 x $.65 is $3.25., and he multiplied by US/GB
Nadene is incorrect because she took GB/US x 5
Answer:
70
Step-by-step explanation:
20x(1+150%)
28x(1+1.5)
28x2.5
70
Consider the charge for parking one car for t hours.
If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.
If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.
75% is 75/100 or 0.75.
For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be
0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:
3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].
Thus, the function which total parking charge of parking 3 cars for t hours is:
</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1))
Answer: C</span>
Answer:
The answer is 600 minutes (10 hours)
Step-by-step explanation:
20 minutes = 1 student.
30 students x 20 = 600 minutes
600mins / 60 (because an hour has 60 mins) = 10 hours.
