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3 years ago

15

There were 10 baked goods in a basket.four of them were sold.write a fraction to show the part of the baked goods that were not

sold .

1 answer:

aleksklad [387]3 years ago

5 0

Try subtracting first there were 10 then four were sold I don't know what happens after but thats what I know

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Solve this equation with substitution method :-<br> x+5 = 3 (y+5)<br> x-5 = 7 (y-5)

Damm [24]

From the first equation,
x+5 = 3(y+5)
x = 3y + 15 - 5
Now substitue x in the second equation with (3y +15 - 5).
x-5 = 7(y-5)
(3y+15-5) - 5 = 7(y-5)
3y +5 = 7y - 35
-4y = - 40
y = 10

Since y is 10, and x is (3y +15 - 5),
x = 30 + 15 - 5 = 40

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3 years ago

16ml=________mg what is 16 milliliters as milligrams

statuscvo [17]

There is 1 gram is a milliliter and grams to milligrams is 16,000
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3 years ago

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Charles will babysit for up to 4 hours and charges $7 per hour. Write a function in function notation for this situation.

I am Lyosha [343]

Assume Charles charges $7*3=$21 if he babysits for 2,5 hours (that is 2 and a half hours).

That is we are not considering Charles babysitting exactly 1, 2, 3 or 4 hours, but also in between times.

then we can write the following piecewise function to describe the situation:

f is a function from (0, 4] to {$7, $14, $21, $28}

$f(x)=\begin{cases} 
 \$7 & if \enspace \enspace x\leq 1 \\
 \$14 & if \enspace \enspace 1\ \textless \ x\leq 2 \\
 \$21 & if \enspace\enspace 2\ \textless \ x\leq 3 \\
 \$28 & if \enspace\enspace 3\ \textless \ x\leq 4 \
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3 years ago

Which function represents a translation of the parent cubic function 8 units to the left? h(x) = x3 + 8 h(x) = x3 – 8 h(x) = (x

Ksju [112]

Using the definition of the Vertical shifts of graphs of the function :

"Suppose c>0,

To graph y=f(x)+c, shift the graph of y=f(x) upward c units.

To graph y=f(x)-c, shift the graph of y=f(x) downward c units"

Again we recall the definition of Horizontal shifts of graphs:

" suppose c>0,

the graph y=f(x-c), shift the graph of y=f(x) to the right by c units

the graph y=f(x+c), shift the graph of y=f(x) to the left by c units. "

consider $f(x)=x^3$ is the parent function.

$h(x)=x^3+8$ shifts the graph $f(x)=x^3$ upward by 8 units

$h(x)=x^3-8$ shifts the graph $f(x)=x^3$ downward by 8 units

$h(x)=(x+8)^3$ shifts the graph $f(x)=x^3$ left by 8 units

$h(x)=(x-8)^3$ shifts the graph $f(x)=x^3$ right by 8 units.

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3 years ago

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Solve for each system of equations by substitution or elimination.

Tems11 [23]

QUESTION 1

The given system of equations are:

$y=x^2+5x+1$

$y=x^2+2x+1$

We equate the two equations to get:

$x^2+5x+1 =x^2+2x+1$

$x^2 - {x}^{2} + 5x - 2x = 1 - 1$

$3x = 0$

$x = 0$

When x=0,

$y=0^2+2(0)+1 = 1$

The solution is (0,1)

QUESTION 2

The given equations are:

$y=x^2-2x - 1$

and

$y= -x^2-2x-1$

We equate both equations to get:

$x^2-2x - 1 = -x^2-2x-1$

Group similar terms,

$x^2 + {x}^{2} -2x + 2x= -1 + 1$

$2 {x}^{2} = 0$

$x = 0$

We put x=0 into any of the equations to find y.

$y= -0^2-2(0)-1 = - 1$

The solution is (0,-1).

QUESTION 3

The given equations are:

$y=x^2+2x+1$

and

$y=x^2+2x-1$

We equate both equations:

$x^2+2x+1 = x^2+2x-1$

Group similar terms:

$x^2 -x^2+2x = -1 - 1$

$0 = -2$

This is not true.

Hence the system has no solution.

6 0

3 years ago