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1 year ago

A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive

1 answer:

6 0

If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.

Calculation for the Amount of IV

It is given that,

1L IV contains 60meq of kcal

⇒ 1000 mL of IV contains 60meq of kcal

⇒ 1 mL of IV will contain 60 / 1000 meq of kcal

As per the question,

The amount of IV infused in the patient = 400 mL

⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)

= 4 × 6

= 24 meq of kcal

Hence, the patient receives 24meq of kcal amount of IV.

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Arte-miy333 [17]

X=30
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Cross multiply and get 27x= 45 x 18
Or 27X = 810.
Next, divide by 27 on both sides to get X=30.

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3 years ago

45 POINTS!!!!!!!!!!

yanalaym [24]

Y-3 is the correct answer

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3 years ago

What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D

Ivahew [28]

Answer:

4 and -10

Step-by-step explanation:

$\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a} \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a} = \frac{-6-14}{2}=\frac{-20}{2} = -10$

4 0

3 years ago

Which expression represents the volume, in cubic units, of the shaded part of the sphere? four-thirdsπ(103) four-thirdsπ(43) fou

oee [108]

The volume of the shaded part in cubic units is 4/3π(20)³ - 4/3π(4)³

<h3>Volume of composite object</h3>

The sphere is a a solid 3-dimensional object. THe formula for calculating its volume is expressed as:

V = 4/3πr³

where:

r is the radius of the sphere

<u>For the outer sphere:</u>

V = 4/3π(20)³

<u>For the inner sphere:</u>

V = 4/3π(4)³

The volume of the shaded part in cubic units is 4/3π(20)³ - 4/3π(4)³

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6 0

2 years ago

Can i get help? Don’t really understand.

Rufina [12.5K]

First option: correct. This is because angles WOX and XOZ are supplementary, so

$m\angle WOX=180^\circ-104^\circ=76^\circ$

Second option: correct. By the inscribed angles theorem, we have

$m\angle XWZ=m\angle XYZ=\dfrac{113^\circ}2=56.5^\circ$

Angles WOX and YOZ are congruent because they form a vertical pair; they both have measure 76 degrees. This means angles WXY and WZY are also congruent, since the interior angles of any triangle sum to 180 degrees in measure. Therefore triangles WXO and YZO form a side-side-side pair, and all SSS triangles are similar.

Third option: not correct. There is a theorem (not sure what the name is) regarding intersecting chords that asserts the average of the measures of arcs WY and XZ is the same as the measure of angle XOZ. This means

$\dfrac{m\widehat{WY}+113^\circ}2=104^\circ\implies m\widehat{WY}=95^\circ$

Fourth option: not correct. This is because arcs WX and XZ are not "supplementary" in the sense that they do not form a semicircle and their measures do not add to 180 degrees. We know this because it's clear that point O is not the center of the circle. If it was, then angle XOZ would be a central angle and its measure would be the same as the arc XZ it subtends.

Fifth option: correct. The theorem mentioned in the assessment of the third option makes itself useful here. We have

$\dfrac{m\widehat{WX}+m\widehat{YZ}}2=m\angle WOX\implies m\widehat{WX}+m\widehat{YZ}=2\cdot76^\circ=152^\circ$

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2 years ago