$\frac{-2}{3}x+9=\frac{4}{3}x-3\\\\\frac{-2}{3}x-\frac{4}{3}=-3-9\\\\\frac{-2-4}{3}x= - 12\\\\\frac{-6}{3}x = -12\\\\ -2x -12\\\\x = \frac{-12}{-2}\\\\x = 6$

3 0

3 years ago

PLEASE HELP! urgent! Write the equation of a line in a slope-intercept form and standard form

m_a_m_a [10]

Answer:

$y = \frac{3}{4}x -3$ --- Slope intercept

$4y - 3x =- 12$ --- Standard form

Step-by-step explanation:

Given

The attached linear graph

Required

The equation

Select any two points on the line

$(x_1,y_1) = (0,-3)$

$(x_2,y_2) = (4,0)$

Next, calculate the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

So, we have:

$m = \frac{0 --3}{4 - 0}$

$m = \frac{3}{4}$

The slope intercept is then calculated using:

$y = m(x - x_1) + y_1$

So, we have:

$y = \frac{3}{4}(x - 0) -3$

$y = \frac{3}{4}(x) -3$

$y = \frac{3}{4}x -3$

Multiply through bu 4

$4y = 3x - 12$

Subtract 3x from both sides

$4y - 3x =- 12$ --- Standard form

7 0

3 years ago