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choli [55]
3 years ago
5

Jojo likes to paint. She estimates the number of paintings she completes using the function P of w equals two thirds times w min

us two, where w is the number of weeks she spends painting. The function J(y) represents how many weeks per year she spends painting. Which composite function would represent how many paintings Jojo completes in a year?
Mathematics
2 answers:
pantera1 [17]3 years ago
3 0

Answer:

P = \frac{2}{3} [J(y)] - 2

Step-by-step explanation:

If Jojo completes P number of paintings working w weeks then the relation between P and w is given by P = \frac{2}{3} w - 2. ........ (1)

Again, the function J(y) represents how many weeks per year she spends painting.

So, w = J(y). ...... (2)

Therefore, the composite function which represent how many paintings Jojo completes in a year, is given by  

P = \frac{2}{3} [J(y)] - 2  (Answer)

Andrej [43]3 years ago
3 0

Answer:

p{j(y)}=2/3*j(y)-2

Step-by-step explanation:

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question says Miranda is thinking of a number. She says, "If I multiply it by 5 and then subtract 3 and then multiply the result
OlgaM077 [116]

Answer:

4

Step-by-step explanation:

To make your equation, you basically write all the steps down with x as your number and then set it equal to 34 (wow, that was very confusing, sorry!). This means that your equation would be (5x-3)2=34. Now, you'll solve this by starting with distributing the 2 (2*5x and 2*-3), which will give you the equation 10x-6=34. Next, add six to both sides (10x-6+6=10x and 34+6=40), so you should get 10x=40. Lastly, divide both sides by 10 (10x/10=x and 40/10=4) to get x=4. I'd also advise checking your answer by multiplying 4 by 5 (20), then subtracting 3 (20-3=17), and multiplying it by 2 (2*17=34). :)

8 0
3 years ago
Working alone at its own constant rate, a machine seals k cartons in 8 hours, and working alone at its own constant rate, a seco
Harlamova29_29 [7]

Answer:

66\dfrac{2}{3}\%

Step-by-step explanation:

Given,

The number of cartons = k,

Time taken by machine a = 8 hours,

So, the number of cartons made by machine a in one hour

= \frac{\text{Cartons in 8 hours}}{8}

= \frac{k}{8}

Time taken by machine b = 4 hours ,

So, the number of cartons made by machine b in one hour

= \frac{k}{4}

Total cartons made in 1 hour = \frac{k}{8}+\frac{k}{4}

=\frac{k+2k}{8}

=\frac{3k}{8}

∵ for the whole number value of k,

\frac{k}{4}>\frac{k}{8}

i.e.  machine b is faster,

Also, the percent of the cartons were sealed by the machine b

=\frac{\text{Cartons made in 1 hour by machine b}}{\text{Total cartons}}\times 100

=\frac{\frac{k}{4}}{\frac{3k}{8}}\times 100

=\frac{2}{3}\times 100

=\frac{200}{3}

=66\dfrac{2}{3}\%

Hence, OPTION D is correct.

5 0
3 years ago
99 POINT QUESTION
rewona [7]
We assume you intend h(t) to be the usual equation of ballistic motion
  h(t) = -16t² + 40t + 10

a. The function can be written in vertex form as
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  h(t) = -16(t² -5/2t +(5/4)²) + 10 +5²
  h(t) = -16(t -5/4)² + 35
This is the vertex form a(x-h)²+k where (h, k) is the vertex of the parabola. The maximum height will be "k" for a < 0, which it is.

The ball's maximum height is 35 ft.


b. h(t) = 0 for the value of t that satisfies
  0 = -16(t -5/4)² + 35
  (t -5/4)² = 35/16
  t = (5 +√35)/4 ≈ 2.729
About 2.729 seconds have passed when the ball hits the ground.


_____
I find it convenient to let a graphing calculator tell you the answers to these questions. As above, the maximum height is the y-coordinate of the vertex. The elapsed time is the x-coordinate of the positive x-intercept.

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3 years ago
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ololo11 [35]
The answer would be 3 hours or at 3 pm
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3 years ago
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