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3 years ago

This morning, Yolanda's car had 29.44 gallons of fuel. Now, 4.6 gallons are left. How much fuel did Yolanda use?

1 answer:

8 0

The answer is 24.84 because 29.44-4.6 is 24.84
to double check you can add (after you subtract and get your answer) 24.84 and 4.6 and get 29.44

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Which measurement statement is correct? There are 2 cups in a pint. There are 2 pints in a cup. There are 4 quarts in a pint. Th

anzhelika [568]

There are 2 cups in a pint

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3 years ago

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Harriet needs to ship a small vase. The box she will use has a volume of 216 cubic inches. If the side lengths are all the same,

ArbitrLikvidat [17]

Fist if there is 4 sides on the base you would divide 216/4 =54

Or if there are 2 sides you would divide 216/2= 108

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3 years ago

Draw an area model that demonstrates that the quotient of 2080 and 40 is 52.

Scrat [10]

Area model is used to illustrate multiplication and division operations.

See attachment for the area model

The equation can be represented as:

$\frac{2080}{40} = 52$

Express 2080 as 1200 + 800 + 80

$\frac{1200 + 800 + 80}{40}=52$

Express as

$\frac{1200 + 800 + 80}{40}=\frac{1200}{40} + \frac{800}{40} + \frac{80}{40}$

Divide

$\frac{1200 + 800 + 80}{40}= 30 + 20 + 2$

See attachment for the area model

Read more about area models at:

brainly.com/question/18533236

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2 years ago

A sample of 12 measurements has a mean of 16.5, and a sample of 15 measurements has a mean of 18.6. Find the mean of all 27 meas

Wewaii [24]

Answer: $17.67$

Step-by-step explanation:

Given

Sample of 12 measurements has a mean of 16.5 and

a sample of 15 measurements has a mean of 18.6

Take $\bar{x_1},n_1$ be the mean and no of measurements

and $\bar{x_2},n_2$ be the mean and no of measurements in second case

$\therefore \bar{x_1}=\dfrac{\sum a_1}{n_1}\\\\\Rightarrow \sum a_1=\bar{x_1}\times n_1\\\\\Rightarrow \sum a_1=198\quad \ldots(1)$

Similarly,

$\therefore \bar{x_2}=\dfrac{\sum a_2}{n_2}\\\\\Rightarrow \sum a_2=\bar{x_2}\times n_2\\\\\Rightarrow \sum a_2=279\quad \ldots(2)$

Mean of 27 measurements

$\Rightarrow \bar{x_3}=\dfrac{\sum a_1+\sum a_2}{n_1+n_2}\\\\\Rightarrow \bar{x_3}=\dfrac{198+279}{12+15}\\\\\Rightarrow \bar{x_3}=\dfrac{477}{27}\\\\\Rightarrow \bar{x_3}=17.67$

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3 years ago

What is the answer to 40x + 24

olchik [2.2K]

Answer:

8(5x+3)

Step-by-step explanation:

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3 years ago