Answer:
y^2 +7y-30
Step-by-step explanation:
Step 1: Use FOIL
y·y = y^2
y· 10= 10y
-3·y= -3y
-3·10= -30
Step 2: <em>combine like terms</em>
y^2+ 10y-3y-30
7^2+ 7y-30
and thats all :)
hope this helped
Due to the fact he does not know how many people are attending, you would represent the people value with a variable. Because we know he's given 8 ox. per person, you would need to write the expression as 8x.8 to represent the ox. needed and the x representing the people.
Divide 32 by 8 to see how many people he can serve,
32/8=4
Answer:
m∠LNK = 86.8°
Step-by-step explanation:
∵ LH ⊥ KN at H
∵ LK = MN
∵ LM = 3
∴ HN = (13 - 3) ÷ 2 + 3 = 8 ⇒ isosceles trapezium
∵ LN = 89
∴ LH = √(89² - 8²) = 88.64
∵ KH = (13 - 3) ÷ 2 = 5 ⇒ isosceles trapezium
∵ tan ∠LKN = LH/KH = 88.64/5
∴ m∠LKN = 86.77° ≅ 86.8°
Answer:
The full Question is attached in the picture below.
PR = 5(9) +28 = 73
Step-by-step explanation:
Since the figure is a rectangle
SQ = PR
11x-26 = 5x +28
6x = 54
x = 9
Answer:
x ≈ 263.1
Step-by-step explanation:
The marked sides are the hypotenuse and the side adjacent to the given angle. The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
cos(70°) = 90/x . . . . use given values
x = 90/cos(70°) . . . . multiply by x/cos(70°)
x ≈ 263.1
_____
<em>Additional comment</em>
The mnemonic SOH CAH TOA is intended to remind you of the primary trig relations:
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
Tan = Opposite/Adjacent
