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poizon [28]
3 years ago
6

Defenition of exponent

Mathematics
2 answers:
sdas [7]3 years ago
7 0

Answer:

The definition of an exponent is..

Step-by-step explanation:

A quantity representing the power to which a given number or expression is to be raised, usually expressed as a raised symbol beside the number or expression (e.g. 3 in 23 = 2 × 2 × 2).

Hope this helped >,<

aivan3 [116]3 years ago
5 0

An exponent is a quantity representing the power to which a given number or expression is to be raised, usually expressed as a raised symbol beside the number or expression (e.g. 3 in 23 = 2 × 2 × 2).

In other words, an exponent represents how many times you multiply (or divide) a value by itself.

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Jamal simplified ...
brilliants [131]
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4 0
3 years ago
GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m
Harrizon [31]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 3.50 mg  

     Alternate Hypothesis, H_A : \mu > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average mg of mercury in compact fluorescent bulbs.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, H_A : \mu > 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                          T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean mg of mercury = 3.59

            \sigma = population standard deviation = 0.18 mg

            n = sample of bulbs = 25

So, <em><u>test statistics</u></em>  =  \frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }

                               =  2.50

The value of z test statistics is 2.50.

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 2.50) = 1 - P(Z \leq 2.50)

                                             = 1 - 0.9938 = 0.0062

<em />

<em>Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0
3 years ago
Can all quadrilaterals be inscribed in a circle? Explain
-BARSIC- [3]
Depends of the size of the quadrilateral in relation to the circle, but otherwise, yes
3 0
3 years ago
Which equation has the least steep graph? A. y = x + 6 B. y = -x - 9 C. y = 2x + 1 D. y = -7x - 2
maria [59]

Answer:

A and B.

Step-by-step explanation:

<h3>To get to know the graph with least slope, we have to write all equations in the form <u>y=mx + c. </u></h3>

where m is the slope and c is the the y-intercept.

A. y = x + 6

For this equation m = 1

B. y = -x - 9  

For equation B, m = -1

C. y = 2x + 1  

In this equation, m = 2  

D. y = -7x - 2

In equation D, m = -7

The equation with the highest slope is D while the one with the least slope/steep is <em>A and B.</em>

3 0
3 years ago
Read 2 more answers
The number of candies in a large bag of M&amp;M decreased by 25% between
Kruka [31]

Answer:

the answer is 45 candies in the bag this year.

Step-by-step explanation:

60×.25=15

60-15=45

4 0
3 years ago
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