All categories

3 years ago

Defenition of exponent

Mathematics

2 answers:

sdas [7]3 years ago

7 0

Answer:

The definition of an exponent is..

Step-by-step explanation:

A quantity representing the power to which a given number or expression is to be raised, usually expressed as a raised symbol beside the number or expression (e.g. 3 in 23 = 2 × 2 × 2).

Hope this helped >,<

aivan3 [116]3 years ago

5 0

An exponent is a quantity representing the power to which a given number or expression is to be raised, usually expressed as a raised symbol beside the number or expression (e.g. 3 in 23 = 2 × 2 × 2).

In other words, an exponent represents how many times you multiply (or divide) a value by itself.

You might be interested in

Jamal simplified ...

brilliants [131]

$\bf \sqrt{75x^5y^8}\qquad 
\begin{cases}
75=3\cdot 25\\
\qquad 3\cdot 5^2\\
x^5=x^{4+1}\\
\qquad x^4x^1\\
\qquad (x^2)^2x\\
y^8=y^{4\cdot 2}\\
\qquad (y^4)^2
\end{cases}\implies \sqrt{3\cdot 5^2\cdot (x^2)^2x(y^4)^2}
\\\\\\
5x^2y^4\sqrt{3x}$

4 0

3 years ago

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m

Harrizon [31]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

Let $\mu$ = average mg of mercury in compact fluorescent bulbs.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean mg of mercury = 3.59

$\sigma$ = population standard deviation = 0.18 mg

n = sample of bulbs = 25

So, test statistics = $\frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }$

= 2.50

The value of z test statistics is 2.50.

Now, P-value of the test statistics is given by;

P-value = P(Z > 2.50) = 1 - P(Z $\leq$ 2.50)

= 1 - 0.9938 = 0.0062

Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0

3 years ago

Can all quadrilaterals be inscribed in a circle? Explain

-BARSIC- [3]

Depends of the size of the quadrilateral in relation to the circle, but otherwise, yes

3 0

3 years ago

Which equation has the least steep graph? A. y = x + 6 B. y = -x - 9 C. y = 2x + 1 D. y = -7x - 2

maria [59]

Answer:

A and B.

Step-by-step explanation:

<h3>To get to know the graph with least slope, we have to write all equations in the form y=mx + c. </h3>

where m is the slope and c is the the y-intercept.

A. y = x + 6

For this equation m = 1

B. y = -x - 9

For equation B, m = -1

C. y = 2x + 1

In this equation, m = 2

D. y = -7x - 2

In equation D, m = -7

The equation with the highest slope is D while the one with the least slope/steep is A and B.

3 0

3 years ago

Read 2 more answers

The number of candies in a large bag of M&M decreased by 25% between

Kruka [31]

Answer:

the answer is 45 candies in the bag this year.

Step-by-step explanation:

60×.25=15

60-15=45

4 0

3 years ago