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yaroslaw [1]
3 years ago
13

The altitude of an object, d, can be modeled using the equation below. d=-16t^2+vh+h.where v is the initial velocity and h is th

e initial height.A catapult launches a stone with an initial velocity of 48 feet per second and an initial height of 0 feet. How long will the stone be in flight?
Mathematics
1 answer:
finlep [7]3 years ago
6 0

Answer:

The stone will be in flight for 3 seconds

Step-by-step explanation:

Given the equation;

d = -16t^2 + vt + h

Where;

v = the initial velocity

h = the initial height

Given;

v = 48 ft/s

h = 0

Substituting into function d;

d = -16t^2 + 48t + 0

d = -16t^2 + 48t

At the point of launch and the point of landing d = 0.

We need to calculate the values of t for d to be equal to zero.

d = -16t^2 + 48t = 0

-16t^2 + 48t = 0

Factorising, we have;

16(-t+3)t = 0

So,

t = 0 or -t+3 = 0

t= 0 or t =3

Change in t is;

∆t = t2 - t1 = 3 - 0

∆t = 3 seconds.

The stone will be in flight for 3 seconds.

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Answer:

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(21 , 8) ⇒ 5th

Step-by-step explanation:

To find the solution of the graph let us make the equation of the line by using any two points on the line

The form of the linear equation is y = m x + b, where

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The formula of the slope is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

From the figure

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∴ m=\frac{1-0}{0--3}=\frac{1}{3}

- Substitute the value of m in the form of the equation

∴ y = \frac{1}{3} x + b

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∴ b = 1

∴ y = \frac{1}{3} x + 1

Lets substitute the x-coordinate of each point to find the y-coordinate, if the y-coordinate is equal to the y-coordinate of the points, then the point is a solution

Point (-15 , -4)

∵ x = -15

∴ y = \frac{1}{3} (-15) + 1

∴ y = -5 + 1 = -4 ⇒ same value of the point

∴ (-15 , -4) is a solution

Point (-6 , 1)

∵ x = -6

∴ y = \frac{1}{3} (-6) + 1

∴ y = -2 + 1 = -1 ⇒ not the same value of the point

∴ (-6 , 1) is not a solution

Point (3 , 2)

∵ x = 3

∴ y = \frac{1}{3} (3) + 1

∴ y = 1 + 1 = 2 ⇒ same value of the point

∴ (3 , 2) is a solution

Point (12 , 9)

∵ x = 12

∴ y = \frac{1}{3} (12) + 1

∴ y = 4 + 1 = 5 ⇒ not the same value of the point

∴ (12 , 9) is not a solution

Point (21 , 8)

∵ x = 21

∴ y = \frac{1}{3} (21) + 1

∴ y = 7 + 1 = 8 ⇒ same value of the point

∴ (21 , 8) is a solution

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