All categories

2 years ago

Can two obtuse angles be verticle?

Mathematics

1 answer:

MariettaO [177]2 years ago

7 0

I assume when you say vertical you mean a straight line.

If so, then the answer is NO, two obtuse angles cannot be vertical. Obtuse angles have to be greater than 90 degrees, so the least an obtuse angle can be is 91 degrees.

91 + 91 = 182, and a straight line is 180 degrees.

So two obtuse angles cannot be vertical because even the lowest degrees that two obtuse angles can be is greater than 180 degrees (a straight line).

You might be interested in

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

6 0

2 years ago

Line "AB" and line "CD" are perpendicular and intersect at point P. What is the measure of angle APC?

Step2247 [10]

Answer:

APC is 90 degrees

Step-by-step explanation:

When lines intersect and are perpendicular. that means the angle of intersection is 90 degrees.

APC is 90 degrees

7 0

3 years ago

Read 2 more answers

At Lakeview middle school,there are 2 homeroom teachers assigned to every 48 students. is the number of stuff at this school pro

Zielflug [23.3K]

Yes becuase constant rate will be 24/1
and when you keep subtracting 1 to the x value & and 24 to y value it will end with 0,0 meaning its proportion

6 0

2 years ago

The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out

Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$