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2 years ago

Find the value of x to the nearest tenth!

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

5 0

Answer:

5.7

Step-by-step explanation:

sine cosine tangent

soh cah toa

sine = opposite/hypotenuse

so sin(35)= x/10

you can multiply 10 to both sides to get rid of the 10 denominator on the right leaving you with 10sin(35)=x

be sure your calculator is in degrees.

put that into a calculator leaving you with 5.7

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A geometric sequence has u4= -70 and u7=8.75<br> Find the second term of the sequence.

Kobotan [32]

Answer:

-122.5

Step-by-step explanation:

Difference = 7 - 4 = 3 terms; 8.75 - (-70) = 78.75

1 term → 78.75/3 = 26.25

therefore, u2 = - 70 - 2(26.25) = -122.5

Topic: Patterns + Common difference

If you would like to venture further into mathematics, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

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2 years ago

The height of a trapezoid is 8 in. And it's area is 96 squared inch. One base of the trapezoid is 6 inches longer than the other

MaRussiya [10]

we name bases k , k+6. so

area: 96= (k + k+6).8/2

=> 2k+6= 24 => k=9

7 0

2 years ago

The data indicate the following approximate percentages:

Mariana [72]

Answer:

Answer 1:

2,147,616

Answer 2:

5,145,330

Answer 3:

3,758,328

Answer 4:

8,157,958

Step-by-step explanation:

These are all correct i got 10/10.

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2 years ago

Brian and 3 of his friends need to collect a total of 1,548 pounds of newspaper for a recycling drive. They will each collect th

KonstantinChe [14]

4 people are collecting

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2 years ago

Read 2 more answers

What is the maximum value of the objective function, P, with the given constraints?

maksim [4K]

Answer:

Option C - 420

Step-by-step explanation:

Given : Objective function, P, with the given constraints

$P=20x+35y$

Constraints,

$x+y \leq 12$

$5x+y \leq 20\\x \geq 0\\y \geq 0$

To find : What is the maximum value

Solution :

First we plot the graph through the given constrains.

As they all move towards the origin the common region of the equations is given by the points (0,0), (0,12), (2,10), (4,0)

Refer the attached figure.

So, we put all the points in P to, get maximum value.

$P=20x+35y$

Point (0,0)

$P=20(0)+35(0)=0$

$P=20x+35y$

Point (0,12)

$P=20(0)+35(12)=420$

Point (2,10)

$P=20(2)+35(10)=40+350=390$

Point (4,0)

$P=20(4)+35(0)=80$

Therefore, The value is maximum 420 at (0,12)

So, Option C is correct.

8 0

2 years ago