All categories

2 years ago

Find the value of x to the nearest tenth!

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

5 0

Answer:

5.7

Step-by-step explanation:

sine cosine tangent

soh cah toa

sine = opposite/hypotenuse

so sin(35)= x/10

you can multiply 10 to both sides to get rid of the 10 denominator on the right leaving you with 10sin(35)=x

be sure your calculator is in degrees.

put that into a calculator leaving you with 5.7

You might be interested in

The size ofa rectangular computer monitor is determined by the length of its diagonal. If a

aivan3 [116]

Sorry, I wish I could help, but I haven't learned this yet

;-;

8 0

3 years ago

Read 2 more answers

Find the area of a rectangle with a base of 5 feet and a height of 9 1/2 feet

gayaneshka [121]

The area of the rectangle is 47 1/2

7 0

2 years ago

While walking for exercise, Mia is able to walk only 3\4 as far on Saturday she walks 1 1/2 miles. How many miles did she walk F

Ket [755]

$1\frac{1}{2} - \frac{3}{4}$
$\frac{3}{2} - \frac{3}{4}$
$\frac{6}{4} - \frac{3}{4}$
= $\frac{3}{4}$

3 0

3 years ago

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

2 years ago

A force of $20$ newtons will stretch a spring $5$ centimeters. What is the total number of centimeters that a force of $60$ newt

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Hooke's Law applies here, which is a linear relationship. It would be easier to solve this using proportions with N of force on the top and the amount of stretch in cm on the bottom. Set up with our unknown, the number of cm:

$\frac{N}{cm}:\frac{20}{5}=\frac{60}{x}$ and cross multiply:

20x = 300 so

x = 15 cm

6 0

2 years ago