The system of equations can be used to find the cost of a night's stay and the cost of a meal is:
2n + 5m = $395
5n + 11m = $959
<h3>
Simultaneous equations</h3>
Simultaneous equations are two or more groups of equations. These equations have to be solved together at the same time in order to determined the required valued. The two above equations have to be solved in order to determine the cost of a night's stay and the cost of a meal.
The methods of determining the required values are:
- Elimination method
- Graph method
- Substitution method
To learn more about simultaneous equations, please check: brainly.com/question/25875552
Answer:
-23
Step-by-step explanation: You have to combine like terms first:
-3.8x -5.9x =223.1
-9.7x = 223.1
Then divide om each side of the equation by -9.7.
-9.7x/-9.7 = 223.1/-9.7
x =- 23
Answer:
18
Step-by-step explanation:
F(10)=3((10)-4) = 18
We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:
Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².
We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3
For 26
ST is = TU
27
2x-1=15
2x=16
X=8