Q in (-oo:+oo)
2/3 = (1/3)*q // - (1/3)*q
2/3-((1/3)*q) = 0
ddddddddd
d d
d d
(-1/3)*q+2/3 = 0 d d
d d
2/3-1/3*q = 0 // - 2/3 d d
d d
-1/3*q = -2/3 // : -1/3 d d
d d
q = -2/3/(-1/3) ddddddd dddddddd
dd dd
q = 2 dd dd
dd dddd dd
q = 2 dddddddddd dddddddddddd
Answer:
300ml
Step-by-step explanation:
As values are missing in your question, the complete question is:
In the lab, Leila has two solutions that contain alcohol and is mixing them with each other. Solution A is 6% alcohol and Solution B is 20% alcohol. She uses 400 milliliters of Solution A. How many milliliters of Solution B does she use, if the resulting mixture is a 12% alcohol solution?
Considering x=ml of 20% solution B
Therefore, 400+x=ml of resulting 12% solution
Solution A alcohol+ solution B alcohol= Alcohol solution
6% (400)+ 20%x = 12%(400+x) ->(converting percentage into decimal)
.06*400+.2x=.12(400+x)
24+.2x=48+.12x
.08x=24
x=24/.08=300 ml
she used 300 milliliters of 20%Solution B in resulting mixture.
Answer:
It’s a
Step-by-step explanation:
Answer:
Sorry, I only know the answer to B.
Step-by-step explanation:
The answer is 0=0, 2=5, 4=10, 6= 15. Sorry if I am late. But I hope this helps, and Have an amazing day!!
7(x+y) because their both factors of 7
