The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)
How to partition a Line segment?
The formula to partition a line segment in the ratio a:b is;
(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]
We want to find point G on AB such that the ratio of AG to GB is 3:2.
From the graph, the coordinates of the points A and B are;
A(3, 5) and B(5, 0)
Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;
G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]
G(x, y) = (21/5, 10/5)
G(x, y) = (4.2, 2)
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For this case we must solve the following system of equations:

We multiply the first equation by -2:

We add the new equation with the second one:

We have different signs subtracted and the sign of the major is placed:

Now we find the value of the variable "y":

Thus, the solution of the system is given by:

Answer:

<span> y - x3 - 9x2 - 27x - 37 = 0 is this what you were looking for?</span>
Answer:
it wil be 96
Step-by-step explanation:
85 88 and 97 are all numbers that contributet to the exponentialalty ogf this number 96