I don’t know because you don’t show any chart
Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
The scale is a representation of what the drawing is to real life. The drawing will tend to be represented by a fixed figure such as 1 cm. In this case for every cm of drawing it is a representation of 8 millimetres in real life, therefore the drawing is bigger than the object.
Answer:
- boat: 6 mph
- current: 2 mph
Step-by-step explanation:
The relationship between time, speed, and distance is ...
speed = distance/time
For boat speed b and current speed c, the speed downstream is ...
b +c = (16 mi)/(2 h) = 8 mi/h
The speed upstream is ...
b -c = (16 mi)/(4 h) = 4 mi/h
Adding the two equations eliminates the c term:
2b = 12 mi/h
b = 6 mi/h . . . . . divide by 2
Solving the second equation for c, we get ...
c = b -4 mi/h = 6 mi/h -4 mi/h = 2 mi/h
The speed of the boat in still water is 6 mi/h; the current is 2 mi/h.
Answer:
Number 3 is correct.
129.19m
Step-by-step explanation:
You might be wondering how did I got 32⁰, well, that's because they are alternate angles.
Now, we're trying to find the opposite side of the triangle.
Using the laws,
we got cos32⁰=x/243.8
243.8cos32⁰=x
129.19⁰
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