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Paladinen [302]
3 years ago
6

Solve the system of linear equations by elimination. 3x+2y=3 3x−2y=−9

Mathematics
1 answer:
kondaur [170]3 years ago
6 0

Answer:

x=-1, y=3

Step-by-step explanation:

3x+2y=3

3x-2y=-9

since we have -2y and 2y we can just add the equations

6x=-6

x+0y=-1

x=-1

to solve x using elimination multiply the top equation by -1

-3x-2y= -3

3x-2y=-9

and add

0x-4y=-12

-4y=-12

y=3

and substitute x and y to double; check

3(-1)+2(3)=3

-3+6=3

3=3

checks out so these are correct

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tresset_1 [31]

(a) Truck carries 90 gallons of diesel fuel to 660 miles.

So, 1 gallon of diesel fuel to 660/90 = 22/3 miles.

30 gallons of diesel fuel to  = 220 miles.

Hence, if x-axis represents the number of miles and y-axis represents the number of gallons, then, (660, 90) and (220, 30) are points on the graph.

Join (660, 90) and (220, 30), we get the graph of a line.

Note that (0, 0) is also a point on the line.

Equation of the line is .

(b) x represents the number of miles. Therefore, the possible values for x is the closed interval [0, 660].

Hence, the domain of the function is [0, 660].

(c) Origin represents that the truck is not moving and there is no diesel fuel loaded in the truck.

7 0
3 years ago
Please help me with this problem
Alexus [3.1K]
(a) It is leaking 18 liters per minute.

Explanation : From 15 minutes to 20 minutes, your starting point at 15 is 590 liters and at 20 you have exactly 500. Next you have 25 which is now at 410. So it's leaking 90 liters every five minutes, so of course dividing the two (90 ÷ 5) you get 18.

(a)² it increases for about the same time that it would decrease of course.

(b) The vat started at 860 liters before they started draining it.

Explanation : Well, all it takes is just working backwards, add 90 liters to the liters at 15 minutes and deduct five minutes from 15. Do this process until you arrive at 0. It's simple
7 0
3 years ago
2 7/8 plus 3 2/8 plus 1 1/8
Olin [163]

Answer:

7.25

Step-by-step explanation:

2 7/8 + 3 2/8 * 1 1/8 = 7.25

7 0
3 years ago
Read 2 more answers
Help please!<br><br> | 2x^2 + 5x + 3 | &gt; 0<br> solve the inequality
vovikov84 [41]

Factorize the quadratic.

2x^2 + 5x + 3 = (2x + 3) (x + 1)

We have |ab| = |a||b|, so

|2x^2 + 5x + 3| = |2x + 3| |x + 1| > 0

Now, both |2x+3|\ge0 and |x+1|\ge0 (since the absolute value of any number cannot be negative), so we just need to worry about when the left side is exactly zero. This happens for

(2x + 3) (x + 1) = 0 \implies 2x+3 = 0\text{ or }x+1 = 0 \\\\ \implies x = -\dfrac32 \text{ or } x = -1

So the solution to the inequality is the set

\left\{x \in \Bbb R \mid x\neq-\dfrac32 \text{ and } x\neq-1\right\}

3 0
2 years ago
find the 20th term of an arithmetic sequence with a first term of 3 and a common difference of 5. a. 87 b. 98 c. 101 d. 130
Nady [450]
The formula for the nth term of an arithmetic sequence is:
n_{th} \ term=a+(n-1)d
where a is the first term and d is the common difference.
Plugging the given values into the formula, we get:
20th\ term=3+(20-1)5=98
The answer is b. 98.

3 0
3 years ago
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