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3 years ago

12

Simón has already walked 3 kilometers this week, plus he has plans to walk 2 kilometers during each trip to school wrote an equa

tion that shows the relationship between the number of trips t and the total distance waked d.

1 answer:

fenix001 [56]3 years ago

8 0

2t+3=d

t = every trip 2 schools

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Find the simple interest on a loan of:

Nikolay [14]

Answer:

simple interest= 5100

using formula SI=<u> </u><u>PTR</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>100

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7 0

3 years ago

Two trains started moving at the same time, train A from Boston to New York, and train B from New York to Boston. The distance b

elena55 [62]

Answer:

2 hours

Step-by-step explanation:

Train B's speed: 4/3 × 60 = 80

Combined speed = 80 + 60 = 120

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8 0

4 years ago

Please help will make brainliest. Write the equation of a line that is parallel to y=9 and that passes through the point (3,-8)

kow [346]

Answer:

y= -8

Step-by-step explanation:

$\frac{y- y1}{x- x1} = \frac{y + 8}{x - 3} = m$

where m is the slope of the line.

m= 0 which is equal to the slope of the line y=9

because both are parallel.

$y + 8 = 0(x - 3)$

$= > y = - 8$

4 0

3 years ago

A magazine printed photos of three celebrities along with three photos of the celebrities as babies. The baby pictures did not i

Anna35 [415]

The probability of matching the first one correctly is 1/3 .
Then there are only two baby-pix left, so ...
The probability of matching the second one correctly is 1/2 .
Then there's only one baby-pic left, so ...
The probability of matching the third one correctly is 1 .

So the probability of matching all three correctly is

(1/3) x (1/2) x (1) = 1/6 = (16 and 2/3) percent .

5 0

4 years ago

Read 2 more answers

Rationalise:<br>(1) 4/(2+root3+root7)<br>(2) 4/(2root3+root5)

Temka [501]

$\frac{4}{2+\sqrt3+\sqrt7}\cdot\frac{2-(\sqrt3+\sqrt7)}{2-(\sqrt3+\sqrt7)}=\frac{8-4\sqrt3-4\sqrt7}{2^2-(\sqrt3+\sqrt7)^2}=\frac{8-4\sqrt3-4\sqrt7}{4-3-2\sqrt{3\cdot7}-7}\\\\=\frac{8-4\sqrt3-4\sqrt7}{-6-2\sqrt{21}}=\frac{-2(2\sqrt3+2\sqrt7-4)}{-2(3+\sqrt{21})}=\frac{2\sqrt3+2\sqrt7-4}{3+\sqrt{21}}\cdot\frac{3-\sqrt{21}}{3-\sqrt{21}}\\\\=\frac{6\sqrt3-2\sqrt{63}+6\sqrt7-2\sqrt{147}-12+4\sqrt{21}}{3^2-(\sqrt{21})^2}=\frac{6\sqrt3-2\sqrt{9\cdot7}+6\sqrt7-2\sqrt{49\cdot3}-12+4\sqrt{21}}{9-21}$

$=\frac{6\sqrt3-6\sqrt7+6\sqrt7-14\sqrt3-12+4\sqrt{21}}{-12}=\frac{-8\sqrt3+4\sqrt{21}-12}{-12}=\frac{-4(2\sqrt3-\sqrt{21}+3)}{-12}\\\\=\frac{2\sqrt3-\sqrt{21}+3}{3}$

==============================================================

$\frac{4}{2\sqrt3+\sqrt5}\cdot\frac{2\sqrt3-\sqrt5}{2\sqrt3-\sqrt5}=\frac{8\sqrt3-4\sqrt5}{(2\sqrt3)^2-(\sqrt5)^2}=\frac{8\sqrt3-4\sqrt5}{4\cdot3-5}=\frac{8\sqrt3-4\sqrt5}{12-5}\\\\=\frac{8\sqrt3-4\sqrt5}{7}$

4 0

4 years ago

Read 2 more answers