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Effectus [21]
3 years ago
9

7TH GRADE MATH!!! PLZ HELP WILL MAKE BRAINLIEST AND THANKS!

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer: A, C, D

If you try plugging in a few different numbers into these equations, you will get only 1 result.

:)

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Simply this expression (3x+ 1/2) + (7x - 4 1/2
never [62]
Add like terms
10x - 4
3 0
3 years ago
Read 2 more answers
AAAAA PLEASE HELPPP
Harrizon [31]

Answer:

200.96

Step-by-step explanation:

The formula to do these is radius x radius x pi since we arent given radius we have to figure it out but we know radius is just half of the diameter so 16 ÷ 2 = 8 then we do 8 × 8 = 64 then we do 64 × 3.14 = 200.96 Hope this helps! sorry I forgot something when rounded to the tenths place its 201.0

3 0
2 years ago
Jordan wants to solve the following system using the elimination method:
denis-greek [22]
In the first equation, we have 3y. In the second equation we have y.

If we multiply the second equation by 3, then if we subtract both the equations, we will be able to eliminate y.

If we multiply the second equation by -3, then if we add both the equations, we will be able to eliminate y.

The answer to your question is: 3 and -3.
7 0
3 years ago
Read 2 more answers
All Parent functions have both x- intercepts and y-intercepts EXCEPT. I. Linear II. Absolute Value III.Quadratic IV. Cubic V.Squ
stealth61 [152]

Answer:

Reciprocal, Exponential and Logarithmic.

Step-by-step explanation:

x intercept is the value of x where y value is 0.

y intercept is the value of y where x value is 0.

Let us have a look at the possibility for <em>each parent function </em>as given.

I. Linear

y =x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

II. Absolute value

y =|x|

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

III. Quadratic

y =x^{2}

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

IV. Cubic

y =x^3

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

V. Square root

y =\sqrt x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

VI. Cube root

y =\sqrt[3]x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

VII. Reciprocal

y =\dfrac{1}x

When x = 0, y \rightarrow \infty

Therefore, both x and y intercept do not exist.

VIII. Exponential

y =b^x

where b is any base:

When x = 0, y =1 therefore y intercept exists.

When we put y = 0, which is not possible

Therefore, both x and y intercept do not exist.

IX. Logarithmic

y =logx

When x = 0, y \rightarrow not defined

Therefore, both x and y intercept do not exist.

6 0
3 years ago
4x + 4y +/2 =24<br> 2x-44 +2=0<br> 45x -44-52=12
V125BC [204]

Answer:

(no solutions exist)

Step-by-step explanation:

7 0
2 years ago
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