it will take 1.33 hours for Braydon and Lauren to get to the same mile marker on the path in the park .
<u>Step-by-step explanation:</u>
Here we have , Braydon can run at 3 miles per hour , he's initially at 10 mile marker . Lauren is at the 12-mile marker at the park, She is walking at a pace of 1.5 miles per hour. We need to find How long will it take for Braydon and Lauren to get to the same mile marker on the path in the park .Let's find out:
Let after time t they meet each other so , Braydon can run at 3 miles per hour , he's initially at 10 mile marker . Distance traveled is given by :
⇒ 
Now , Lauren is at the 12-mile marker at the park, She is walking at a pace of 1.5 miles per hour , Distance traveled is given by :
⇒ 
Equating both we get :
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , it will take 1.33 hours for Braydon and Lauren to get to the same mile marker on the path in the park .
Answer:
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Answer:
2nd option
Step-by-step explanation:
The shaded area = outside area - inner area
= x² - (x - 6)² ← expand using FOIL
= x² - (x² - 12x + 36) ← distribute parenthesis by - 1
= x² - x² + 12x - 36 ← collect like terms
= 12x - 36
You just want to simplify right?!
45. (a^2b^3)(ab)^-2
= (a^2b^3)(a^-2b^-2)
= b
46. (-3x^3y)^2(4xy^2)
= (-9x^6y^2)(4xy^2)
= -36x^7y^4
47. 3c^2d(2c^3d^5) / 15c^4d^2
= 6c^5d^6 / 15c^4d^2
= 2/5c1/4x^4
48. -10g^6h^9(g^2h^3) / 30g^3h^3
= -10g^8h^12 / 30g^3h^3
= -1/3g^5h^9
49. 5x^4y^2(2x^5y^6) / 20x^3y^5
= 10x^9y^8 / 20x^3y^5
= 1/2x^6 1/3y^3
50. -12n^7p^5(n^2p^4) / 36n^6p^7
= -12n^9p^9 / 36n^6p^7
= -1/3n^3p^2
(Sorry it’s messy it’d look better if my phone could actually put the numbers to the power)