the scale of map is 1cm to 8km , two towns are 52km apart . how far apart are the two towns on the map

Simplify fully<br> 13/2x-5/x

Vaselesa [24]

Answer:

13x2−10/2 is your answer

Step-by-step explanation:

5 0

3 years ago

I need fast help!!!!!!!!! Please

german

Answer:

x= −5/ 2 + 1 /2 √21 or x= −5 /2 + −1/ 2 √21

Step-by-step explanation:

7 0

3 years ago

The ages of the 32 recruits in police academy are normally distributed with a mean of 27 with a standard deviation of 2. What is

aksik [14]

Since it's a sample size, we use x, as the mean and s= standard deviation
_
Given: x =27, s = 2 and total sample = 32.
Probability that a recruit is at least 31 years old?

Let's calculate the Z score :
_
X - x 31 - 27
Z = ----------- → Z = -------- → Z = 2 (now look up in the Z score table,
s 2

Area (Z=2) =0.9772 , but Z ≥ 2 (at least) , then :
Area (Z≥2) = Area (Z≤ - 2) = 0.0228

P(≥31)= 0.0228

7 0

3 years ago

Pls help I’ll brainlest and add extra points<br><br> Just do number 1

Lapatulllka [165]

Answer:

B

Step-by-step explanation:

While reading, I felt like the quote was in an angry tone. It sounded like the author wanted the Devil to know that he was ready to attack him in vengeance and questioned why the Devil wasn't afraid.

8 0

3 years ago

Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.

DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

$\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}$

$\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A$

$\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B$

$M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$

Location of P

$\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}$

$\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A$

$\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M$

$\vec P = \frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B$

$P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$

Location of Q

$\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}$

$\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P$

$\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M$

$\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)$

$\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B$

$Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

We kindly invite to check this question on midpoints: brainly.com/question/4747771

4 0

2 years ago