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3 years ago

Yo who tryn do a zo.o00m call at 3

Mathematics

2 answers:

steposvetlana [31]3 years ago

7 0

Answer:

later

Step-by-step explanation:

lara [203]3 years ago

6 0

Answer:

call at 3 ???

what that means

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Someone please help me with this!

Sveta_85 [38]

5(14-2)^2/2

5( 12)^2/2

Do the exponent

5(12*12)/2

5(144)/2

144/2= 72

72*5= 360

Answer : 360

8 0

3 years ago

Can someone help me with this please

e-lub [12.9K]

Answer: y=-2x+6

Step-by-step explanation:

$m=\frac{6-2}{0-2}=\frac{4}{-2}=-2$

So $y=2x+b$ . We can substitute (0, 6) to get:

6 = 2(0)+b

b=6.

Meaning y=-2x+6.

8 0

3 years ago

URGENT HELP PLEASE.

AlladinOne [14]

W + 2w = 60

this equation is wrong

6 0

3 years ago

Marvin has a vintage comic book worth $351. According to a dealer, the value of this particular comic book will increase by 12.1

White raven [17]

Y = 12.1% x 13 + 351
y= 0.012 x 13 + 351
y= 1.573 + 351
y= 352.573 or $352.6

3 0

2 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

3 years ago