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Simora [160]
3 years ago
7

A store sells apples and oranges. Apples cost $2.00 per pound, and oranges cost $3.00 per pound. Jenny purchased 1 3/4 pounds of

apples
and 2 1/2 pounds of oranges. How much did Jenny spend on apples and oranges?
Mathematics
2 answers:
user100 [1]3 years ago
5 0
The answer is $10.25
Naily [24]3 years ago
3 0

Answer: $10.25

Step-by-step explanation: Jenny bought 1 3/4 pounds of apples, and each pound is $2, so that would be $2.75. And she also bought 2 1/2 pounds of oranges, and each pound is $3, so that would be $7.50.

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Kryger [21]

Answer: 15n³-105n²+2n+16/6n²-42n

Step-by-step explanation:

n+8/3n²-21n +5n/2

2(n+8)+5n(3n²-21n)/2(3n²-21n)

2n+16+15n³-105n²/6n²-42n

15n³-105n²+2n+16/6n²-42n

7 0
4 years ago
HELP 15 POINTS<br> Write a rule for the nth term of the sequence. Then find a20 -<br> 51,48,45,42
garri49 [273]

Answer:

45 because it is what I think

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3 years ago
Evaluating a piece-wise function. 10 pts
kozerog [31]
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4 0
2 years ago
-n+(-4)-(-4n)+6<br><br><br> solve
tigry1 [53]

Answer:

3n + 2

Step-by-step explanation:

-n+(-4)-(-4n)+6

= -n -4 +4n +6        [positive plus negative =  negative; ∴  +(-4) = -4

=4n - n +6 - 4                      negative plus negative = positive; ∴ -(-4n) = 4]

now subtract n from 4n and subtract 4 from 6

=3n + 2

                                                                                                       

                             

8 0
3 years ago
Read 2 more answers
The volume of a cone of radius r and height h is given by V=πr²h³. If the radius and the height both increase at a constant rate
Aloiza [94]

Answer:

The volume of cone is increasing at a rate 1808.64 cubic cm per second.

Step-by-step explanation:

We are given the following in the question:

\dfrac{dr}{dt} = 12\text{ cm per sec}\\\\\dfrac{dh}{dt} = 12\text{ cm per sec}

Volume of cone =

V = \dfrac{1}{3}\pi r^2 h

where r is the radius and h is the height of the cone.

Instant height = 9 cm

Instant radius = 6 cm

Rate of change of volume =

\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{1}{3}\pi r^2 h)\\\\\dfrac{dV}{dt} = \dfrac{\pi}{3}(2r\dfrac{dr}{dt}h + r^2\dfrac{dh}{dt})

Putting values, we get,

\dfrac{dV}{dt} = \dfrac{\pi}{3}(2(6)(12)(9) + (6)^2(12))\\\\\dfrac{dV}{dt} =1808.64\text{ cubic cm per second}

Thus, the volume of cone is increasing at a rate 1808.64 cubic cm per second.

5 0
3 years ago
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