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DENIUS [597]
3 years ago
12

Write the missing number 98,46

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0
The missing number is 28
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Find f^-1(x) and it’s domain.
Mrac [35]

Answer: A

Step-by-step explanation:

Letting f(y)=x,

x=\sqrt{y}-5\\\\x+5=\sqrt{y}\\\\y=(x+5)^{2}

Also, the domain of an inverse is the same as the range of the original function, so the range is x \geq 0

7 0
2 years ago
What is the sum of the next two terms in the sequence: -3, -1, 3, 9, 17
Korvikt [17]
Answer: 66 because you are adding 2 then 4 then 6 then 8 then 10 then 12 therefore 17+10= 27, and 27+12= 39 and 39+27 equals 66
6 0
3 years ago
What do you think the answer is
amid [387]
23/69 is about fashion
4 0
3 years ago
given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ
rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0
3 years ago
In each diagram, linek is parallel to line 1, and line t intersects lines k and l.
abruzzese [7]

Answer:

Step-by-step explanation:

A

7 0
3 years ago
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