the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
t/3 is your expression.
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900 - 250 = 650
650 / 250 = 13 / 3 = 2.6 = 260%
The method of computing that would result in a greater finance charge is a. the daily balance method will have a finance charge $1.02 greater than the adjusted balance method.
<h3>What is the Adjusted Balance Method?</h3>
This refers to the method of accounting that makes use of the owed amount of money at the end of a billing cycle to make its computation on an account after the credits are calculated.
Hence, we can see that when comparing the adjusted balance method to the daily balance method that calculates the interest charges at the end of the day, the daily balance method would have a higher finance charge.
Read more about adjusted balance methods here:
brainly.com/question/1808408
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Answer:A
Step-by-step explanation: your answer is A
