A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection ac
ross the (x-axis, y-axis, line y=x, line x=y) followed by a translation (4 units to the right an 10 units up, 8 units to the right and 4 units up, 10 units to the right and 2 units up, 10 units to the right and 4 units up)
2 answers:
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Answer:
Step-by-step explanation:
First, we can find the slope using the slope equation and two of the points.
Slope equation:
I'm going to use the first two points just so I can avoid the fraction... Substitute the x and y values into the equation.
Simplify:
Now that we have the slope, all we need is the y-intercept. Luckily, it gives it to us in the table. The x value of y-intercepts will always be 0. Looking at the table, we see that the point where x=0 is (0,2). Thus, the y-intercept is 2. Your final equation is