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gizmo_the_mogwai [7]
3 years ago
5

An artist makes 50 note cards. She puts the note cards in packages to sell. She puts 5 note cards in each package. She sells all

the packages of note cards. She earns $8 for each package she sells. What is the total amount of money the artist earns from selling the packages of note cards
Mathematics
1 answer:
Artemon [7]3 years ago
5 0

Answer:

$80

Step-by-step explanation:

50/5= 10  this determines how many packages of cards she has

10 * $8 = $80  multiply the number of packages of cards by $8

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1/6divid by 5 and I need help for my sis that is 2
elixir [45]

Answer:

The answer is 5/6

Step-by-step explanation:

1/6 x 5 is 5/6. You can do 1 x 5 which is 5. You don't need to multiply anything else. The answer is 5/6

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4 years ago
7x^2+3y^2+12x+2y-6=0 Help me find the value of a,b,c and the discriminant number
Mrac [35]

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b o a h d

Step-by-step explanation:

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7 0
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Does anyone know how to get more points in khan academy mastery challenge??
vaieri [72.5K]

Answer:

I would say getting all the them right.

Step-by-step explanation:

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A cylinder has a height of 12 feet and a radius of 5 feet. What is its volume? Use ​ ≈ 3.14 and round your answer to the nearest
beks73 [17]

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Step-by-step explanation:

The formula for the volume of a cylinder is  v = pi* r^2 * h

Where v is the volume, r is the radius and h is the height.

Input the values for pi, radius, and the height into the formula to solve for the volume.

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7 0
3 years ago
How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

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0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

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x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

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3 years ago
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