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icang [17]
3 years ago
15

I need help with math

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
6 0
It is the top one I know
dybincka [34]3 years ago
3 0
Translation will be your answer, for it just moved, but didn't change

hope this helps

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Which expression is equivalent to 7(5t)?
Dafna11 [192]

Answer:

35+7t

Step-by-step explanation:

7(5t) {If you expand it}

7×5+7×t

35+7t

3 0
3 years ago
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Describe a real world problem you could solve with the help of a yardstick and a calculator.
jekas [21]
There are many options, let me tell you three
- how many square feet is your house
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I hope these options are useful
4 0
3 years ago
What is the value of minus 6(-2)cubed - 4 squared - 3(-2x4)?
iogann1982 [59]

Find the value of -6(-2)^2 - 4^2 - 3(-2x^4).

-6(-2)^2 - 4^2 - 3(-2x^4)

Multiply -6(-2)^2.

12^2 - 4^2 - 3(-2x^4)

Subtract 12^2 and -4^2.

8 - 3(-2x^4)

Distribute -3(-2x^4).

8 + 6x^4

Therefore the value of 6(-2)^2 - 4^2 - 3(-2x^4) is 8 + 6x^4.

6 0
3 years ago
What would I have to do here? Somebody please help me! (Look at the bottom problem not the top)
Zinaida [17]
Alright, let's do this! If $25 is one fifth of how much the game system cost then, multiply 25 times 5. And you should get your answer. 
I hope this helps. 
8 0
3 years ago
According to the MIT Airline Data Project, American Airlines controlled 15.5% of the domestic market during a recent year. A ran
Naya [18.7K]

Answer:

0.0143

Step-by-step explanation:

In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.

We proceed as follows;

The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155

Let’s call this probability p

The probability that he/she isn’t on the flight, let’s call this q

q =1 - p= 0.845

Sample size, n = 155

P(X < A) = P(Z < (A - mean)/standard deviation)

Mean = np

= 125 x 0.155

= 19.375

Standard deviation = √npq

= √ (125 x 0.155x 0.845)

= 4.0462

P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)

= P(Z < (10.5 - 19.375)/4.0462)

= P(Z < -2.19)

= 0.0143

4 0
3 years ago
Read 2 more answers
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