Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
You can set them equal to each other so -3x+4=4x-10 and then you add 3x and 10 on both sides and get7x=14 and then divided both sides by 7 and get x = 2 and check by plugging in and you get -2 for y on both so solution is x=2
Answer: $3.8 per pound of food.
Step-by-step explanation: 18.24 divided by 4.8
Answer:
-22
Step-by-step explanation:
Solve the expression using PEMDAS.
-19 + 3(-13 + 4 * 3)
~Multiply
-19 + 3(-13 + 12)
~Add
-19 + 3(-1)
~Multiply
-19 - 3
~Subtract
-22
Best of Luck!
Convert decimals to fractions
Multiply both sides by 10
Move expression to the left.
Remove zero.
Solve the quadratic equation.
Remove parenthesis and calculate.
Add the numbers
Separate the solutions
The final solution are
