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2 years ago

9

Mary and Mike went to the store to buy colored pencils for their science class.mike bought a 12-pack for 1.69,and Mary bought a

24-pack for 3.18
Which was the better buy?

1 answer:

sweet-ann [11.9K]2 years ago

3 0

12-pack for 1.69 is a better buy

<em><u>Solution:</u></em>

Given that, Mike bought a 12-pack for 1.69 and Mary bought a 24-pack for 3.18

We have to find which is the better buy

First we have to find the unit rate

Unit rate is cost of 1 pack

<em><u>Mike bought a 12-pack for 1.69</u></em>

Therefore,

Cost of 12 pack = 1.69

Cost of 1 pack is found by dividing 1.69 by 12

$cost\ of\ 1\ pack = \frac{1.69}{12} = 0.14083$

Thus unit rate of Mike is 0.14083 dollar per pack

<em><u>Mary bought a 24-pack for 3.18</u></em>

Cost of 24 pack = 3.18

Cost of 1 pack is found by dividing 3.18 by 24

$cost\ of\ 1\ pack = \frac{3.18}{24} = 0.1325$

Thus unit rate of Mary is 0.1325 dollars

<em><u>On comparing both the unit rate</u></em>

$0.14083>0.1325$

Thus unit rate of Mike is larger

Thus, 12-pack for 1.69 is a better buy

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Answer:

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$y = 20x +80$ --- Tim

Step-by-step explanation:

Given

Sam Tim

х --- f(x) --------------- g(x)

1 --- 80 --------------- 100

2 --- 110 --------------- 120

3 --- 140 --------------- 140

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First, we need to take any corresponding values of x and y

$(x_1,y_1) = (1,80)$

$(x_2,y_2) = (4,170)$

Next, we calculate the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{170 - 80}{4 - 1}$

$m = \frac{90}{3}$

$m = 30$

Next, we calculate the line equation using:

$y - y_1=m(x-x_1)$

$y - 80 = 30(x - 1)$

$y - 80 = 30x - 30$

Make y the subject

$y = 30x - 30 + 80$

$y = 30x +50$

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First, we need to take any corresponding values of x and y

$(x_1,y_1) = (1,100)$

$(x_2,y_2) = (4,160)$

Next, we calculate the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

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$m = \frac{60}{3}$

$m = 20$

Next, we calculate the line equation using:

$y - y_1=m(x-x_1)$

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Make y the subject

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Solve step by step solution then only i can do it plxx

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Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

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Now in $\triangle ABD$

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We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

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$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

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