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pishuonlain [190]
3 years ago
9

Joshua had two-sevenths of all the goals scored by is soccer team. His team scored 28 goals this past season. How many goals did

the rest of the team score? 1 point
Mathematics
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

Rest of the team= 20 goals

Step-by-step explanation:

Giving the following information:

Joshua= (2/7)

His team scored 28 goals this past season.

<u>First, we determine hoy many goals Joshua score:</u>

Joshua= (2/7)*28

Joshua= 8 goals

<u>Now, the rest of the team:</u>

Rest of the team= 28 - 8

Rest of the team= 20 goals

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The center on a target has a diameter of 5 inches. The whole target has a diameter of 25 inches. The center of the target takes
Komok [63]
4%

To find the percentage, first find the area of both circles. The area formula is \pi  r^{2} . After finding the area of the center of the target (19.625) and the area of the large target (490.625), set up a percent proportion to determine the percentage that the center takes up: 

\frac{is}{of} =  \frac{percent}{100}


\frac{19.625}{490.625} =  \frac{percent}{100}


Cross multiplying and dividing by 490.625 will give a total of 4%.



4 0
3 years ago
The half-life of radioactive cobalt is 5.27 years. Suppose that a nuclear accident has left the level of cobalt radiation in a c
sweet [91]

Answer:

  35 years

Step-by-step explanation:

The proportion p that remains after y years is ...

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In order for 1/100 to remain (the level decays from 100 times to 1 times), we have ...

  .01 = .5^(y/5.27)

  log(0.01) = y/5.27·log(0.5) . . . take logs

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5 0
3 years ago
What is electroplating? anyone free to talk?​
Lerok [7]

Answer:

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8 0
3 years ago
Read 2 more answers
ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

7 0
3 years ago
Please help!!! (With one or all the problems, anything is greatly appreciated if you understand probability)
professor190 [17]
Here are the answers to problem 1..

a) 11

b) 5/36

c) 25 Times because 7 has a probability of 16.667%

d) 25 Times because 10, 11, and 12 have a probability sum of 16.667% ironically...

Hope this helps. :)
6 0
3 years ago
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