Ok so we need to set the bottom to 0 to find the vertical asympyotes. This becomes x^2 - 4 = 0. Since we're talking about asymptotes, i'll assume you can solve basic equations. Solving for x and you get x = ±2. This means the vertical asymptotes are at ±2. To solve for horizontal asymptotes you take the limit as x goes to ±∞. Either way you end up with ±∞/∞. Now this isn't 1 because they grow at different rates. You differentiate both the top and bottom(L'hopital) and you get 6x/2x which becomes 3. This means the horizontal asymptote is at y = 3.
Answer:
Zeros: 5, multiplicity 1; -4 multiplicity 2; degree 3
y=1(x-5)^1(x+4)^2
y=(x+4)^2(x-5)
y=(x^2+8x+16)(x-5)
y=x^3+8x^2+16x-5x^2-40x-85
y=x^3+3x^2-24x-85
Step-by-step explanation:
The standard form of linear equations is Ax + By = C where A and B ≠ 0, and A is non-negative.
Therefore, the correct answer is A) 6x - 7y = 8
Answer:
Range - {-4,0,12,20}
Step-by-step explanation:
Given that,
The function is :
g(x) = 4x –12
The domain of the function is {2, 3, 6, 8}.
g(2) = 4(2) –12 = -4
g(3) = 4(3) –12 = 0
g(6) = 4(6) –12 = 12
g(8) = 4(8) –12 = 20
Hence, the range of the function is {-4,0,12,20}.
<span>So,Given that you have A = 23 degrees , B = 21 degrees ,
and side a = 42.8, we find the angle C and the remaining sides of the triangle to be as follows:
Calculating for C = 180 degrees - ( A + B ).
C = 180 - 44 = 136
a / sin A = b / sin B = c / sin C
b = a sin B/ sin A = 42.8 sin 21 / sin 23 = 39.3
c = a sin C/ sin A = 42.8 sin 136/ sin 23 = 76.1
42.8/sin 23 = 109.5
39.3/sin 21 = 109.7
76.1/sin 136 = 109.6
The correct answer is ( c ). C = 136, b = 39.3 , and c = 76.1.</span>
